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Subject:
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Compare parent's attribute with grand parent's one
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Posted By:
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scubaduba
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Post Date:
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11/29/2004 4:40:25 AM
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Hi,
I wanted to compare an element's parent's name attribute with it's grand parent's name attribute. If they match I wanted to print something. The XPath query I used is this, but apparently it didn't work:
<xsl:when test="..[@name]=../..[@name]">
Edit: I see now that it is a wrong syntax.
Here is my XML structure:
<RootElement>
<Groups name='top1'>
<Group name='sub1'>
<Groups name='sub1'>
<Group name="sub1ofsub1"/>
<Group name="sub2ofsub1"/>
<Group name="sub3ofsub1"/>
</Groups>
<Group>
<Groups>
</RootElement>
I can achieve my goal with defining variables for name attributes and comparing them, but if there is a Xpath structure I can use I'd prefere one line code rather than variables.
Thanks in advance.
EDIT: I thought it would be easy to do what I want with variables but I wasn't even able to do that. There is no runtime variable assignment in XSL, which makes things harder.
Here is the XSL structure I tried to get values ( I assume I'm in one of the inner Group elements):
<xsl:template match="Group">
<xsl:variable name="parentsname">
<xsl:value-of select="..[name()='Groups']/[@name]"/>
</xsl:variable>
<xsl:variable name="grandparentsname">
<xsl:value-of select="..[name()='Groups']/..[name()='Group']/[@name]"/>
</xsl:variable>
<!-- Things to be done goes here -->
</xsl:template>
so far I wasn't able to make it work.
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Reply By:
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joefawcett
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Reply Date:
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11/29/2004 6:57:35 AM
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I think you need the curent function in your test:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" method="xml"/>
<xsl:template match="/">
<results>
<xsl:apply-templates/>
</results>
</xsl:template>
<xsl:template match="*">
<xsl:value-of select="name()"/><xsl:text>#x9;</xsl:text>
<xsl:value-of select="../@name"/><xsl:text>#x9;</xsl:text>
<xsl:value-of select="../../@name"/><xsl:text>#xd;</xsl:text>
<xsl:choose>
<xsl:when test="../@name = current()/../../@name">Parent @ name is equal to grandparent @ name</xsl:when>
<xsl:otherwise>Parent @ name is not equal to grandparent @ name</xsl:otherwise>
</xsl:choose>
<xsl:text>#xd;*****************************#xd;</xsl:text>
<xsl:apply-templates/>
</xsl:template>
</xsl:stylesheet>
--
Joe (Microsoft MVP - XML)
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Reply By:
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barcher
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Reply Date:
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11/29/2004 11:20:49 AM
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current() should not be required as both sides of the test will use the current context anyway.
<xsl:if test="../@name=../../@name">using shorthand</xsl:if>
<xsl:if test="parent::*/@name=ancestor::*[2]/@name">using axis</xsl:if>
Regards
Bryan
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Reply By:
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joefawcett
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Reply Date:
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11/29/2004 11:26:42 AM
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Too right, I changed horses midstream and forgot it was no longer needed 
<?xml version="1.0" encoding="UTF-8" ?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" method="xml"/>
<xsl:template match="/">
<results>
<xsl:apply-templates/>
</results>
</xsl:template>
<xsl:template match="*">
<xsl:value-of select="name()"/><xsl:text>#x9;</xsl:text>
<xsl:value-of select="../@name"/><xsl:text>#x9;</xsl:text>
<xsl:value-of select="../../@name"/><xsl:text>#xd;</xsl:text>
<xsl:choose>
<xsl:when test="../@name = ../../@name">Parent @name is equal to grandparent @name</xsl:when>
<xsl:otherwise>Parent @name is not equal to grandparent @name</xsl:otherwise>
</xsl:choose>
<xsl:text>#xd;*****************************#xd;</xsl:text>
<xsl:apply-templates/>
</xsl:template>
</xsl:stylesheet>
--
Joe (Microsoft MVP - XML)
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