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Subject:
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Replacing elements name while grouping.
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Posted By:
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ROCXY
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Post Date:
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1/6/2006 4:40:50 AM
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Hi All,
I have an XML.
<artbody>
<sec>
<heading1>
<verse>Kya, karein mere n;-)</verse>
<verse>Kya, old angry man hoon ;-)</verse>
</heading1>
</sec>
<sec>
<subsec>
<verse>Kya, karein mere n;-)</verse>
<verse>Kya, old angry man hoon ;-)</verse>
</sebsec>
</sec>
</artbody>
XSL used
---------
<xsl:template match="node() | @*">
<xsl:copy>
<xsl:apply-templates select="node() | @*" />
</xsl:copy>
</xsl:template>
<xsl:template match="verse">
<xsl:if test="not(name(preceding-sibling::*[1]) = 'verse')">
<quote>
<xsl:copy-of select=".|following-sibling::verse"/>
</quote>
</xsl:if>
</xsl:template>
<xsl:template match="verse">
<xsl:copy>
<para><xsl:apply-templates/></para>
</xsl:copy>
</xsl:template>
Output XML.
-----------
<artbody>
<sec>
<heading1>
<verse>
<para>Kya, karein mere n;-)</para>
</verse>
<verse>
<para>Kya, old angry man hoon ;-)</para>
</verse>
</heading1>
</sec>
<sec>
<subsec>
<verse>
<para>Kya, karein mere n;-)</para>
</verse>
<verse>
<para>Kya, old angry man hoon ;-)</para>
</verse>
</subsec>
</sec>
</artbody>
---------------------------------------------------------------------
As you see while grouping 'verse', I would like to change child <verse> to <para> and this should happen after grouping all child 'verse' inside 'quote' like this....
....
<quote>
<para>Kya, karein mere n;-)</para>
<para>Kya, old angry man hoon ;-)</para>
</quote>
......
I would greatly appreciate any help provided.
Thanks & Regards,
- ROCXY
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Reply By:
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mhkay
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Reply Date:
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1/6/2006 8:18:55 AM
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You have two template rules that match verse. The XSLT spec is a bit ambivalent on this: it says that it's an error, but the processor doesn't have to report the error, it can recover by choosing the last rule that matches.
What you are trying to achieve is to process the verse twice. The way to do that is with a multi-phase transformation (a mini pipeline). Capture the result of the first transformation in a variable
<xsl:variable name="temp">
<xsl:apply-templates/>
</xsl:variable>
then apply templates to this, in a different mode:
<xsl:apply-templates select="$temp" mode="phase-2"/>
Only, in an XSLT 1.0 processor, you may have to call the vendor's xx:node-set() extension function to make this work:
<xsl:apply-templates select="xx:node-set($temp)" mode="phase-2"/>
where the namespace bound to xx depends on the XSLT processor you are using.
Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference
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Reply By:
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ROCXY
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Reply Date:
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1/6/2006 11:52:45 AM
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Dear kay,
I was trying this syntax but - I dont know how to frame it exactly inside the XSL.
Thanks & Regards,
-ROCXY
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Reply By:
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ROCXY
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Reply Date:
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1/6/2006 12:11:54 PM
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Hi Kay,
I used the following code its working fine.
<xsl:template match="node() | @*">
<xsl:copy>
<xsl:apply-templates select="node() | @*" />
</xsl:copy>
</xsl:template>
<xsl:template match="verse">
<xsl:if test="not(name(preceding-sibling::*[1]) = 'verse')">
<quote>
<xsl:apply-templates select=". | following-sibling::verse" mode="phase1"/>
</quote>
</xsl:if>
</xsl:template>
<xsl:variable name = "temp">
<xsl:apply-templates select="node() | @*" mode="phase1"/>
</xsl:variable>
<xsl:template match="verse" mode="phase1">
<para>
<xsl:apply-templates />
</para>
</xsl:template>
Thanks
-ROCXY
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