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Subject:
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XSL - Parameter query.
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Posted By:
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Neal
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Post Date:
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1/24/2006 9:52:50 AM
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Hi,
I know this may appear easy but please can someone help.
In the example below, am I right in thinking that:
1.
The Parameter name is 'ToOrFrom'
2.
The value to be passed is 'From'
3.
The template to be called is 'DeliveryNotificationHeader'.
<!--Templates called from DeliveryNotificationHeader.xsl-->
<xsl:call-template name="DeliveryNotificationHeader">
<xsl:with-param name="ToOrFrom">From</xsl:with-param>
</xsl:call-template>
I have had limited experience in this field.
Many thanks,
Neal
A Northern Soul
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Reply By:
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mhkay
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Reply Date:
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1/24/2006 10:56:26 AM
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Yes, almost. In fact the value of the parameter is a result-tree-fragment consisting of a document node that owns a text node whose value is "From". For most practical purposes this will behave exactly like passing the string "From", but it's a lot less efficient. It's better to pass the string itself:
<xsl:with-param name="ToOrFrom" select="'From'"/>
Note the nested quotes.
Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference
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Reply By:
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Neal
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Reply Date:
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1/24/2006 11:22:50 AM
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Excellent, very prompt.
So, are there any beneifts in the original code?
(FYI - The template is a separate XSL form)
Thanks again,
Neal
A Northern Soul
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Reply By:
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mhkay
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Reply Date:
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1/24/2006 12:25:58 PM
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There are obviously cases where you do need to build a real result tree fragment (typically it will contain elements) but an RTF that only contains a single text node is always pointless.
Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference
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Reply By:
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mhkay
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Reply Date:
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1/24/2006 12:27:08 PM
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Having said that, there's one case I use them which is
<xsl:variable name="quote">"</xsl:variable>
which is purely for the convenience of not having to escape the quotes.
Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference
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