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Subject:
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Namespace copy problem
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Posted By:
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francislang
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Post Date:
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2/20/2006 8:25:51 AM
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I have an XML document similar to this:
<?xml version="1.0" ?>
<Document xmlns="http://mydomain.com/DocumentSchema.xsd">
<Submission>
<AddressDetails>
<Flat />
<HouseName />
<HouseNumber>1</HouseNumber>
<Street>Test Street</Street>
<District>Test District</District>
<Town>Test Town</Town>
<County>test County</County>
<Postcode>TEST123</Postcode>
</AddressDetails>
<BankDetails>
<SortCode/>
<AccountNumber/>
</BankDetails>
</Submission>
</Document>
I have got a problem with some XSL. Basically I want my output to select all the nodes including <AddressDetails> to give:
<?xml version="1.0" ?>
<AddressDetails>
<Flat />
<HouseName />
<HouseNumber>1</HouseNumber>
<Street>Test Street</Street>
<District>Test District</District>
<Town>Test Town</Town>
<County>test County</County>
<Postcode>TEST123</Postcode>
</AddressDetails>
I think it is the namespace that is causing the issue.
My XSL is as follows:
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:test="http://mydomain.com/DocumentSchema.xsd" exclude-result-prefixes="test">
<xsl:output method="xml" indent="no"/>
<xsl:template match="test:Submission">
<xsl:element name="AddressDetails">
<xsl:copy-of select="*" />
<xsl:apply-templates mode="copy-no-ns" select="node()" />
</xsl:element>
</xsl:template>
<xsl:template mode="copy-no-ns" match="*">
<xsl:element name="{name(.)}" namespace="{namespace-uri(.)}">
<xsl:copy-of select="@*" />
<xsl:apply-templates mode="copy-no-ns" />
</xsl:element>
</xsl:template>
</xsl:stylesheet>
The result includes BankDetails as well.
If I change the xsl:template match to "test:AddressDetails" it errors with "The data at the root level is invalid."
Any help would be most appreciated.
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Reply By:
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mhkay
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Reply Date:
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2/20/2006 10:16:22 AM
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Just add a template rule that throws away the BankDetails:
<xsl:template mode="copy-no-ns" match="test:BankDetails"/>
Also, this is quite wrong:
<xsl:template match="test:Submission">
<xsl:element name="AddressDetails">
<xsl:copy-of select="*" />
<xsl:apply-templates mode="copy-no-ns" select="node()" />
</xsl:element>
</xsl:template>
The xsl:copy-of select="*" copies all children of the Submission, which you don't want. I would get rid of this rule and replace it with
<xsl:template match="/">
<xsl:apply-templates select="//test:AddressDetails"/>
</xsl:template>
The error you report looks like a red herring.
Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference
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Reply By:
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francislang
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Reply Date:
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2/20/2006 10:46:45 AM
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Thanks Mike. That's pretty much it except I'm only getting the data from the XML elements. The nodes appear to be missing.
The following XSL:
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:test="http://mydomain.com/DocumentSchema.xsd" exclude-result-prefixes="test">
<xsl:output method="xml" indent="no" />
<xsl:template match="/">
<xsl:element name="AddressDetails">
<xsl:apply-templates select="//test:AddressDetails/node()" />
</xsl:element>
</xsl:template>
<xsl:template mode="copy-no-ns" match="*">
<xsl:element name="{name(.)}" namespace="{namespace-uri(.)}">
<xsl:copy-of select="@*" />
<xsl:apply-templates mode="copy-no-ns" />
</xsl:element>
</xsl:template>
<xsl:template mode="copy-no-ns" match="test:BankDetails" />
</xsl:stylesheet>
Gives:
<?xml version="1.0" ?>
<AddressDetails>1Test StreetTest DistrictTest Towntest CountyTEST123</AddressDetails>
Is it possible to get the elements as well?
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Reply By:
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mhkay
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Reply Date:
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2/20/2006 12:07:42 PM
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Your terminology is a bit off: an element is a kind of node.
You need to specify mode="copy-no-ns" on the apply-templates call (or remove it from the template rules).
Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference
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