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Subject:
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BINDING DATA WITH SIMPLE CONTROLS
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Posted By:
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saraswathyrajaram
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Post Date:
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8/29/2006 11:36:13 AM
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hi all
how can i bind data in a table with label control?
can i use like this
<asp:label id="lblPrice1" text= '<%# DataBinder.Eval("Price") %>' runat="server"/>
IT SAYS
"Overload resolution failed because no accessible 'Eval' accepts this number of arguments."
CAN ANYONE HELP ME IN THIS CONTEXT
THANKS
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Reply By:
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dparsons
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Reply Date:
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8/29/2006 12:15:35 PM
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The reason you are getting the error is because the Databinder doesnt work like that you have to do:
DataBinder.Eval(Container.DataItem,"Price")
or
Container.DataItem("Price")
hth
"The one language all programmers understand is profanity."
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Reply By:
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saraswathyrajaram
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Reply Date:
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8/29/2006 12:46:18 PM
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I WROTE THE WAY U SAID, BUT IT GIVES
"'DataItem' is not a member of 'System.Web.UI.Control'"
<asp:label id="lblPrice1" text= '<%# DataBinder.Eval(Container.DataItem,"Price") %>' style="Z-INDEX: 102; LEFT: 360px; POSITION: absolute; TOP: 208px"
runat="server"/>PRICE</asp:label>
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Reply By:
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dparsons
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Reply Date:
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8/29/2006 12:52:44 PM
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Remove 'Price' from between your label tags and trying using Container.Dataitem("Price") instead.
"The one language all programmers understand is profanity."
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Reply By:
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saraswathyrajaram
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Reply Date:
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8/29/2006 12:59:40 PM
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<asp:label id=lblPrice1 style="Z-INDEX: 102; LEFT: 360px; POSITION: absolute; TOP: 208px" runat="server" text='<%# DataBinder.Eval(Container.DataItem,"Price") %>'/></asp:label>
BUT THE SAME ERRR
'DataItem' is not a member of 'System.Web.UI.Control'"
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Reply By:
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dparsons
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Reply Date:
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8/29/2006 1:12:49 PM
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I said, try using Container.Dataitem("Price"), remove the databinder.eval.
"The one language all programmers understand is profanity."
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Reply By:
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saraswathyrajaram
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Reply Date:
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8/29/2006 1:17:42 PM
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i am sorry, but its the same result getting
'DataItem' is not a member of 'System.Web.UI.Control'"
<asp:label id=lblPrice1 style="Z-INDEX: 102; LEFT: 360px; POSITION: absolute; TOP: 208px" runat="server" text='<%# Container.DataItem("Price") %>'/></asp:label>
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Reply By:
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dparsons
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Reply Date:
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8/29/2006 1:30:11 PM
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The Databinder.Eval and Container.DataItem are designed to work inside of controls you have called Databind() on;
For example:
DataGrid.DataSource = DataTable;
DataGrid.DataBind();
If your label control is not inside a parent control that you are calling DataBind on, then you have to pragmatically set the text property:
foreach(DataRow dr in datatable){
lblPrice1.text = dr["price"];
}
of course, if you are just returning just one row you dont need the for each loop, you can simply reference the column in the row that holds the data you want displayed in the label.
"The one language all programmers understand is profanity."
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Reply By:
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saraswathyrajaram
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Reply Date:
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8/29/2006 2:05:43 PM
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Dim dc As DataColumn
Dim dr As DataRow
For Each dr In Ds.Tables(0).Rows
For Each dc In Ds.Tables(0).Columns
lblPrice1.text= dr(dc.["Price"].ToString())
Next
Next
IT SAYS "IDENTIFIER EXPECTED" NEAR ["Price"].ToString())
IS THIS THE CORRECT FORMAT OF "FOR LOOP" IN VB.NET?
THANKS
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Reply By:
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dparsons
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Reply Date:
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8/29/2006 2:08:08 PM
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you wouldnt use the second for loop; and you cant use C# braces [ ] in VB.
"The one language all programmers understand is profanity."
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Reply By:
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saraswathyrajaram
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Reply Date:
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8/29/2006 2:28:29 PM
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Dim dc As DataColumn
Dim dr As DataRow
For Each dr In Dstrail1.Tables(0).Rows
lblPrice1.Text = dr(dc."Price".ToString() )
I AM SORY, STILL IT SAYS,, "IDENTIFIER REQIRED"
Next
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Reply By:
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dparsons
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Reply Date:
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8/29/2006 2:38:42 PM
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There are variances in C# and vb, and this case is no different.
In vb, you must qualify the column you are referencing with .item so:
dr.item("Price")
You do NOT call a data colum object inside of datarow object.
"The one language all programmers understand is profanity."
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Reply By:
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saraswathyrajaram
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Reply Date:
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8/29/2006 3:01:50 PM
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thanks i got that error corrcted,
but i am struggling with some more code
shall i seek ur advice
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Reply By:
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dparsons
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Reply Date:
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8/29/2006 3:09:02 PM
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post in the forums someone will answer it.
"The one language all programmers understand is profanity."
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