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Subject:
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Database Management Problem
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Posted By:
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talk2learner
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Post Date:
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12/20/2006 12:18:26 PM
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I am feeling problem when I post or retrieve values in/form databas. Function is made by me which is called by the form page , but values are not posted in database. No error declared by browser:-
function select()
{
$qry = "select * from donarinfo where pk_id=7";
$row=mysql_query($qry);
$result= mysql_select_db($databaseName);
return $result;
}
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Reply By:
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jhanny007
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Reply Date:
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12/20/2006 2:21:11 PM
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hi try like this:
{
$qry = "SELECT * from donarinfo
WHERE pk_id=7";
$result= mysql_select_db($qry)or die(mysql_error());
$row=mysql_query($result);
extract ($row);
}
______________________________________
.::If you quit you loss, If you survive you win::.
.::JHANNY::.
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Reply By:
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surendran
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Reply Date:
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12/21/2006 11:47:44 PM
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try with this,
$link = mysql_connect('localhost', 'user', 'pass')
OR die(mysql_error());
mysql_select_db("databasename",$link)or die("did not select database");
$sql="SELECT * from donarinfo WHERE pk_id=7";
$result = mysql_query($sql);
while($row = mysql_fetch_array($result))
{
extract ($row);
}
surendran
(Anything is Possible)
http://ssuren.spaces.msn.com
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Reply By:
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vivekananth
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Reply Date:
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1/25/2007 12:09:39 AM
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i am new
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Reply By:
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vivekananth
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Reply Date:
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1/25/2007 12:10:59 AM
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how to create a database in mysql through php
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