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Subject:
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Delimiter for loop that may have blank rows
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Posted By:
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kwerle
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Post Date:
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11/25/2003 1:57:14 PM
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I have data that looks like this:
<parent>
<child>
<info>bar</info>
</child>
<child>
<data>foo</data>
<info>bar</bar>
</child>
<child>
<info>bar</info>
</child>
<child>
<data>foo</data>
<info>bar</bar>
</child>
</parent>
Really, the info nodes are more complex and have their own template.
In short, what I'd like to do is output all the data and info for any children that have a data node, with a delimiter between:
foo
bar
---
foo
bar
So I want the data, followed by the info, followed by a delimiter IF there is another child node with data. The problem is that any child node may or may not have data. This includes the first [n] children, the last [n] children, and any groups of children in the middle. I was thinking that following-sibling:: was going to solve my problem, but that fails if there is a gap anywhere but the end.
How can this be done?
TIA,
Kurt
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Reply By:
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armmarti
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Reply Date:
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11/26/2003 1:12:34 AM
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(not tested)
...
<xsl:template match="/">
<xsl:apply-templates select="parent/child[data]"/>
</xsl:template>
<xsl:template match="child[data]">
<xsl:value-of select="data"/><br/>
<xsl:value-of select="info"/><br/>
<xsl:if test="following-sibling::child[data]">
---<br/>
</xsl:if>
</xsl:template>
...
Regards,
Armen
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Reply By:
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kwerle
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Reply Date:
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11/26/2003 12:25:08 PM
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That does the trick, sure enough.
Thanks!
kwerle
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