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Subject:
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XSLT Templates
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Posted By:
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bmains
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Post Date:
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12/16/2003 9:14:00 AM
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Hello,
I have the following XML:
<Documents>
<Section Title="Documentation" Sidebar="false">
<Document>...</Document>
<Document>...</Document>
<Document>...</Document>
</Section>
<Section Title="Business Information" Sidebar="false">
<Document>...</Document>
<Document>...</Document>
<Document>...</Document>
</Section>
<Section Title="Policy" Sidebar="true">
<Document>...</Document>
<Document>...</Document>
<Document>...</Document>
</Section>
</Documents>
What I want to do is trigger a different response when the sidebar is true then when false. In my stylesheet, I had did this:
<xsl:template match="Documents">
<table>
<tr>
<td>
<xsl:apply-templates select="Section[@Sidebar != 'true']"/>
</td>
<td width="20%">
<xsl:apply-templates select="Section[@Sidebar = 'true']"/>
</td>
<tr>
</table>
</xsl:template>
<xsl:template match="Section[@Sidebar = 'true']">
...
</xsl:template>
<xsl:template match="Section[@Sidebar != 'true']">
...
</xsl:template>
The sections where sidebar = true is supposed to be on the right side, and the rest in the main page. I couldn't get this to work. Any ideas what is wrong? How do I render content differently based on the sidebar parameter?
Thanks,
Brian Mains
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Reply By:
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joefawcett
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Reply Date:
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12/16/2003 9:53:00 AM
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Works for me. What do you mean doesn't work? Can you post the full stylesheet?
--
Joe
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Reply By:
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bmains
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Reply Date:
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12/16/2003 1:36:52 PM
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Hello,
I found out the problem I had both a template for:
<template match="Section">
which had defined in it
<for-each select="Document">
However, I had also defined:
<template match="Document">
Which caused a "No result set could be returned" MSXML parser error.
Sorry for any inconvenience.
Thanks,
Brian
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