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asp_web_howto thread: Menu On Left, Selected URL On Right


Message #1 by rg1@h... on Thu, 21 Jun 2001 22:35:38
Hi.



Could somebody please point me where to find some code example of how to 

have a menu on the left 20% of the page and then when the user selects one 

of the items in the menu, the remaining 80% of the page will display the 

URL for the selected item.



I do not want to use frames and was told to use tables but have no idea 

how to get the following code to display in the 80% part of the table:



document.provider.action = "terminatebuild.asp";

document.provider.submit();	



I want "terminatebuild.asp" to appear in the 80% and still have the menu 

visible in the first 20%.



TIA.



Rita
Message #2 by ssteward@a... on Thu, 21 Jun 2001 16:42:21 -0500
if you don't use frames, you'll have to reload the whole page, but you 

can

build the same navigation bar in the left 20% of your page.  just use 

an

.inc file to make your navigation bar and include that in each page...





-----Original Message-----

From: rg1@h... [mailto:rg1@h...]

Sent: Thursday, June 21, 2001 5:36 PM

To: ASP Web HowTo

Subject: [asp_web_howto] Menu On Left, Selected URL On Right





Hi.



Could somebody please point me where to find some code example of how 

to

have a menu on the left 20% of the page and then when the user selects 

one

of the items in the menu, the remaining 80% of the page will display 

the

URL for the selected item.



I do not want to use frames and was told to use tables but have no idea 



how to get the following code to display in the 80% part of the table:



document.provider.action =3D "terminatebuild.asp";

document.provider.submit();=09



I want "terminatebuild.asp" to appear in the 80% and still have the 

menu

visible in the first 20%.



TIA.



Rita





Message #3 by "Parham, Barry" <bparham@n...> on Thu, 21 Jun 2001 16:45:17 -0500

Try using a DIV, SPAN, IFRAME, etc. on the right, and when

the menu events fire, change the object.innerHTML or object. innerTEXT

in the right-side container.



> ~~~~~~~~~~~~

> Barry Parham

> www.the-diaTribe.com

>





-----Original Message-----

From: rg1@h... [mailto:rg1@h...]

Sent: Thursday, June 21, 2001 6:36 PM

To: ASP Web HowTo

Subject: [asp_web_howto] Menu On Left, Selected URL On Right





Hi.



Could somebody please point me where to find some code example of how 

to

have a menu on the left 20% of the page and then when the user selects 

one

of the items in the menu, the remaining 80% of the page will display 

the

URL for the selected item.



I do not want to use frames and was told to use tables but have no idea 



how to get the following code to display in the 80% part of the table:



document.provider.action =3D "terminatebuild.asp";

document.provider.submit();=09



I want "terminatebuild.asp" to appear in the 80% and still have the 

menu

visible in the first 20%.



TIA.



Rita





Message #4 by "Alex Shiell, ITS, EC, SE" <alex.shiell@s...> on Fri, 22 Jun 2001 09:24:07 +0100
if you don't want to use frames then what you need to do is include the 

code

that makes the menu in each page, as an include file.



for example



<TABLE>

<TR>

<TD WIDTH=3D"20%">

<!-- #include file=3D"menu.asp" -->

</TD>

<TD WIDTH=3D"80%">

<%

'ASP code here

%>

</TD>

</TR>

</TABLE>





-----Original Message-----

From: rg1@h... [mailto:rg1@h...]

Sent: 21 June 2001 23:36

To: ASP Web HowTo

Subject: [asp_web_howto] Menu On Left, Selected URL On Right





Hi.



Could somebody please point me where to find some code example of how 

to

have a menu on the left 20% of the page and then when the user selects 

one

of the items in the menu, the remaining 80% of the page will display 

the

URL for the selected item.



I do not want to use frames and was told to use tables but have no idea 



how to get the following code to display in the 80% part of the table:



document.provider.action =3D "terminatebuild.asp";

document.provider.submit();=09



I want "terminatebuild.asp" to appear in the 80% and still have the 

menu

visible in the first 20%.



TIA.



Rita



________________________________________________________________________



Scottish Enterprise Network

http://www.scottish-enterprise.com

Message #5 by Rita Greenberg <rg1@h...> on Fri, 22 Jun 2001 07:30:36 -0700
Terrific. With the include file it's not so clumsy.



Thanks, Rita.



-----Original Message-----

From: Alex Shiell, ITS, EC, SE [mailto:alex.shiell@s...]

Sent: Friday, June 22, 2001 1:24 AM

To: ASP Web HowTo

Subject: [asp_web_howto] RE: Menu On Left, Selected URL On Right





if you don't want to use frames then what you need to do is include the 

code

that makes the menu in each page, as an include file.



for example



<TABLE>

<TR>

<TD WIDTH=3D"20%">

<!-- #include file=3D"menu.asp" -->

</TD>

<TD WIDTH=3D"80%">

<%

'ASP code here

%>

</TD>

</TR>

</TABLE>





Message #6 by Rita Greenberg <rg1@h...> on Fri, 22 Jun 2001 08:45:00 -0700
Hi.



Thanks for your response. That's exactly what Alex suggested.



Rita



-----Original Message-----

From: ssteward@a... [mailto:ssteward@a...]

Sent: Thursday, June 21, 2001 2:42 PM

To: ASP Web HowTo

Subject: [asp_web_howto] RE: Menu On Left, Selected URL On Right





if you don't use frames, you'll have to reload the whole page, but you 

can

build the same navigation bar in the left 20% of your page.  just use 

an

.inc file to make your navigation bar and include that in each page...





-----Original Message-----

From: rg1@h... [mailto:rg1@h...]

Sent: Thursday, June 21, 2001 5:36 PM

To: ASP Web HowTo

Subject: [asp_web_howto] Menu On Left, Selected URL On Right





Hi.



Could somebody please point me where to find some code example of how 

to

have a menu on the left 20% of the page and then when the user selects 

one

of the items in the menu, the remaining 80% of the page will display 

the

URL for the selected item.



I do not want to use frames and was told to use tables but have no idea 



how to get the following code to display in the 80% part of the table:



document.provider.action =3D "terminatebuild.asp";

document.provider.submit();=09



I want "terminatebuild.asp" to appear in the 80% and still have the 

menu

visible in the first 20%.



TIA.



Rita



Message #7 by Rita Greenberg <rg1@h...> on Fri, 22 Jun 2001 08:36:04 -0700
Hi Barry.



Thanks for your response. I can't use IFRAME because it works woth 

FRAME.



I played around with innerHTML and innerText but stopped when I 

realized

that I'd be replacing the innerHTML/TEXT with a URL and didn't think 

that

that would work.



Rita



-----Original Message-----

From: Parham, Barry [mailto:bparham@n...]

Sent: Thursday, June 21, 2001 2:45 PM

To: ASP Web HowTo

Subject: [asp_web_howto] RE: Menu On Left, Selected URL On Right







Try using a DIV, SPAN, IFRAME, etc. on the right, and when

the menu events fire, change the object.innerHTML or object. innerTEXT

in the right-side container.



> ~~~~~~~~~~~~

> Barry Parham

> www.the-diaTribe.com

>





-----Original Message-----

From: rg1@h... [mailto:rg1@h...]

Sent: Thursday, June 21, 2001 6:36 PM

To: ASP Web HowTo

Subject: [asp_web_howto] Menu On Left, Selected URL On Right





Hi.



Could somebody please point me where to find some code example of how 

=3D

to=3D20

have a menu on the left 20% of the page and then when the user selects 

=3D

one=3D20

of the items in the menu, the remaining 80% of the page will display 

=3D

the=3D20

URL for the selected item.



I do not want to use frames and was told to use tables but have no idea 

=3D



how to get the following code to display in the 80% part of the table:



document.provider.action =3D3D "terminatebuild.asp";

document.provider.submit();=3D09



I want "terminatebuild.asp" to appear in the 80% and still have the =3D

menu=3D20

visible in the first 20%.



TIA.



Rita




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