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j2ee thread: question about rmi


Message #1 by "zhebincong" <zhebincong@1...> on Sun, 20 Jan 2002 15:31:43
hello 
i write a simple interface "Hello.java",i want to call it by 
rmi,after "javac","rmic","rmiregistry",i want to start "RMIServer.class" 
that is used to register in the server,see my code: 
==================================================public 
class RMIServer{ 
private static final int PORT=1099; 
private static final String HOSTNAME="127.0.0.1"; 

public RMIServer() 
throws RemoteException, 
MalformedURLException, 
NotBoundException{ 

LocateRegistry.createRegistry(PORT); 
System.out.println("registry:"+HOSTNAME+" in "+(Integer.toString(PORT))); 
Hello h=new HelloImpl(); 
System.out.println("remote object has be created"); 
String urlString="//"+HOSTNAME+":"+Integer.toString(PORT)+"/HelloService"; 
Naming.rebind(urlString,h); 
System.out.println("binding finished"); 
} 

public 
static 
void 
main(String argv[]){ 
System.setSecurityManager(new RMISecurityManager()); 

try{ 
RMIServer rs=new RMIServer(); 
}catch(Exception e){ 
System.err.println(e); 
} 
} 
================================================= 

i type"java RMIServer",it tell me: 

==================================================java.rmi.server.ExportExc
eption: Port already in use: 1099; nested exception is: 

java.net.BindException: Address already in use: JVM_Bind 
================================================== 

then i modify the port number to "10002",it said: 

================================================== 
registry:127.0.0.1 in 10002 
remote object has be created 
java.security.AccessControlException: access denied 
(java.net.SocketPermission 
127.0.0.1:10002 connect,resolve) 
================================================== 

who can tell me why? 
thanks alot 

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