the order of the elements of the web.xml file are wrong

cheers,

JeanLuc

-----Message d'origine-----
De?: Edward [mailto:zhangsc@n...]
Envoy=A8=A6?: vendredi 31 mai 2002 10:29
=A8=A4?: Java 2 Enterprise Edition
Objet?: [j2ee] Why my web.xml is error?
Importance?: Haute


Hello,
 I have a question about servlet's web.xml file,I put my files into 
follows
directories:
D:\Apache Tomcat 
4.0\webapps\login\WEB-INF\classes\GetUserIdentity.class
D:\Apache Tomcat 4.0\webapps\login\WEB-INF\web.xml
D:\Apache Tomcat 4.0\webapps\login\servlets\index.html

My web.xml is follows:

<?xml version=3D"1.0" encoding=3D"UTF-8"?>
<!DOCTYPE web-app
    PUBLIC "-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN"
    "http://java.sun.com/j2ee/dtds/web-app_2_2.dtd">
<web-app>
    <session-config>
     <session-timeout>
        30
     </session-timeout>
    </session-config>
    <welcome-file-list>
     <welcome-file>
        index.html
     </welcome-file>
    </welcome-file-list>
    <servlet>
        <servlet-name>
           GetUserIdentity
        </servlet-name>
        <servlet-class>
           GetUserIdentity
        </servlet-class>
    </servlet>
</web-app>        //---------Here is 24 line---------

When I start Tomcat4.0,I got error:

Starting service Tomcat-Standalone
Apache Tomcat/4.0.1
PARSE error at line 24 column 12
org.xml.sax.SAXParseException: The content of element type "web-app" 
must
match
"(icon?,display-name?,description?,distributable?,context-param*,filter*
,fil
ter-
mapping*,listener*,servlet*,servlet-mapping*,session-config?,mime-mappin
g*,w
elco
me-file-list?,error-page*,taglib*,resource-env-ref*,resource-ref*,securi
ty-c
onst
raint*,login-config?,security-role*,env-entry*,ejb-ref*,ejb-local-ref*)"
.
Starting service Tomcat-Apache
Apache Tomcat/4.0.1

I don't know why my web.xml is error,how to correct it?
Thanks!
Edward