Bibagimon,

I've tried every possible path combination including "/servlet/package-
name.Servlet". When I use this syntax, Tomcat looks for the servlet from 
the "webapps" folder - it loses the path to my web app. Thanks for 
responding though - Tom


> You may test with
action='/servlet/package-name.Servlet'

thanks
bibagimon

--- Tom Berry <tberry@v...> wrote:
> I'm having a problem with my webapps using Tomcat
> 4.1.12. For example, the 
> web app "AdminInv" is at "c:\webapps\admininv". It's
> <Context> in 
> server.xml is: 
> <Context path="/admininv"
> docBase="c:/webapps/admininv" debug="0"/> 
> 
> The web.xml file contains: 
> 
> <servlet-mapping>
> <servlet-name>invoker</servlet-name>
> <url-pattern>/servlet/*</url-pattern>
> </servlet-mapping>
> 
> <welcome-file-list>
> <welcome-file>AdminInventory.html</welcome-file>
> </welcome-file-list> 
> 
> The problem occurs after the login HTML. It accesses
> a servlet 
> ('action="servlet/package-name.Servlet'), which upon
> validation, forwards 
> to an intermediary JSP. Once the servlet is
> accessed, I must add "../" to 
> each URL for JSPs and servlets. Forwarding to JSPs
> from within the servlet 
> also require the "../" I noticed that when the error
> page #404, file not 
> found appears, the URL shows
> "http://localhost/servlet/package-
> name.ServletName", the web app name between
> localhost and servlet is 
> missing. 
> 
> Am I wrong in thinking that I shouldn't need to be
> adding "../" for Tomcat 
> to find the HTMLs, JSPs & servlets? If the web app
> does not use servlets, 
> and so the path is never changed, I don't need to do
> this. Is there 
> something I'm missing in my web.xml files? 
> 
> Thanks
> Tom Berry
> 
> 
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