zXml.js for Chrome

jabadia · #1 (**permalink**) May 5th, 2009, 03:34 PM

Hi,

Testing example from chapter 4 in Google Chrome, I get this error:

uncaught exception TypeError: Property '__load__' of object #<a Document> is not a function

Are there any plans to release a zXml.js lib that is also compatible with Google Chrome?

Thank you,

wctiger · #2 (**permalink**) October 4th, 2009, 06:10 AM

Hi,

I've met similar problems when testing XML cross-browser example from chapter4 in Google Chrome too. My code run well in IE8 & Firefox, but in Chrome there's nothing but blank.
Moreover, even using the example code downloaded from the web, there's still nothing displayed in Chrome.

I'm hoping for a new release of zXml.js which can support Google Chrome better.

Thanks.

jmcpeak · #3 (**permalink**) October 5th, 2009, 10:41 AM

Howdy, folks!

I'll check in with Nicholas and see if he's still supporting the zXml library. If not, I'll update it a bit as time allows in the next few days. In the meantime, you can use an XMLHttpRequest object to grab the XML file and parse it with loadXML(), like this:

Code:

function init() {
    var oXmlDom = zXmlDom.createDocument();
    var oReq = zXmlHttp.createRequest();

    oReq.onreadystatechange = function() {
        if (oReq.readyState == 4) {
            oXmlDom.loadXML(oReq.responseText);
            parseBookInfo(oXmlDom);
        }
    };

    oReq.open("GET", "books.xml", true);
    oReq.send(null);
    
//    var oXmlDom = zXmlDom.createDocument();
//    oXmlDom.onreadystatechange = function () {
//        if (oXmlDom.readyState == 4) {
//            if (oXmlDom.parseError.errorCode == 0) {
//                parseBookInfo(oXmlDom);
//            } else {
//                var str = "An error occurred!!\n" +
//                    "Description: " + oXmlDom.parseError.reason + "\n" +
//                    "File: " + oXmlDom.parseError.url + "\n" +
//                    "Line: " + oXmlDom.parseError.line + "\n" +
//                    "Line Position: " + oXmlDom.parseError.linepos + "\n" +
//                    "Source Code: " + oXmlDom.parseError.srcText;

//                alert(str);
//            }
//        }
//    };
//    oXmlDom.load("books.xml");
}

It isn't perfect by any stretch of the imagination, but it works. Note that since this code uses XMLHttpRequest, the page has to be served from a web server or it will not work.

Need to download code?

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