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Old September 8th, 2005, 05:53 PM
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Default Simple Java Program

Hi there,

I have the following program:

public class e1
{
    public static void main (String[] args){

    byte a = 1;
        while (a<9)
        {
            System.out.println(a);
            a++; †
                †}
        }
}

When I try and compile the program I get the following error:

C:\Java\bookwork>javac e1.java
e1.java:8: possible loss of precision
found†††: int
required: byte
                a = a * 2; ††
                    †† ^
1 error

I know that changing the variable "a" from byte to int fixes this problem but how can I make this code work leaving "a" as a byte?

I hope someone can help

Kindest Regards
WargeMaster
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Old September 9th, 2005, 12:25 PM
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Location: karachi, , Pakistan.
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Default

hello friend

here is your program. i use another variable and do casting for it to solve your problem and 'a' remains byte as well. so you can use both of them according to your need .If it does not solve your problem feel free to share your program idea with me.

public class e1
{
    public static void main (String[] args){

    byte a = 1;
        while (a<9)
        {
            System.out.println(a);
            a++;
    int ab = (int)a*2;
    System.out.println(ab);
                 }
        }
}

TAKE CARE


HumaMunir
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