how to get xml tag names in xslt

mdawoodk · #1 (**permalink**) March 8th, 2005, 03:46 AM

I want to get xml tag names in xslt file. i tried to use name() in value-of but it is giving me wrong result (mag mag), which is the repeatition of the select in for-each. i need result same as "first,second,first,second". my concern is to get the tag names of child elements of tag supplied in for-each's select. it is really urgent.

xml file:-
<mags>
<mag> <first>1</first><second>2</second></mag>
<mag> <first>99</first><second>88</second></mag>
</mags>

xslt logic:-
<xsl:template match="/">
<xsl:for-each select="/mags/mag">
<xsl:value-of select="name()"/>
</xsl:for-each>
</xsl:template>

joefawcett · #2 (**permalink**) March 8th, 2005, 04:42 AM

Something like:

Code:

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text"/>
<xsl:template match="/mags">
  <xsl:apply-templates select="mag/*"/>
</xsl:template>

<xsl:template match="mag/*">
<xsl:value-of select="position()"/><xsl:text>: </xsl:text><xsl:value-of select="name()"/><xsl:text>#xa;</xsl:text>
</xsl:template>
</xsl:stylesheet>

--

Joe (Microsoft MVP - XML)

mdawoodk · #3 (**permalink**) March 8th, 2005, 09:03 AM

First of all thanks for your support i implemented your idea and am getting the following error.
"Top level elements should have non-null namespace, html."
i want to create a table with the tag names. my code is below.

<xsl:transform version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="html" omit-xml-declaration="yes" />

<html>
    <body>
    <xsl:template match="/mags">
        <xsl:apply-templates select="mag/*"/>
    </xsl:template>

    <table width="80%" border="1">
    <tr bgcolor="lightgrey">
        <xsl:template match="mag/*">
            <td>
            <xsl:value-of select="name()"/>
            </td>
        </xsl:template>
    </tr>
    </table>
    </body>
</html>

</xsl:transform>

pgtips · #4 (**permalink**) March 8th, 2005, 10:53 AM

it's because your opening <html> etc isn't inside any xsl template - just put <xsl:template match="/mags"> before it (and remember to close the template after the closing </html>

pgtips · #5 (**permalink**) March 8th, 2005, 10:54 AM

sorry, bad cut and paste. I meant to say
just put <xsl:template match="/"> before it...

mdawoodk · #6 (**permalink**) March 9th, 2005, 02:36 AM

i just added the <xsl:template match="/"> tag before <html> and closed it after </html>. i am getting the following error.

(This is an unexpected token. the expected token is "NAME".)

mdawoodk · #7 (**permalink**) March 9th, 2005, 03:01 AM

sorry about my last reply i am getting the following error not the one i wrote in my last reply.

"'xsl:template' cannot be a child of 'body; element."

pgtips · #8 (**permalink**) March 9th, 2005, 06:11 AM

Apologies, I didn't really look at your stylesheet past noticing that you didn't have a top-level template. I think you need to do a bit more reading about the basics, especially the relationship between xsl:template and xsl:aaply-templates.

Anyway, is this what you want?
<xsl:transform version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <xsl:output method="html"/>
    <xsl:template match="/">
        <html>
            <body>
                <table width="80%" border="1">
                    <xsl:apply-templates/>
                </table>
            </body>
        </html>
    </xsl:template>
    <xsl:template match="mag">
        <tr bgcolor="lightgrey">
            <xsl:apply-templates/>
        </tr>
    </xsl:template>
    <xsl:template match="mag/*">
        <td>
            <xsl:value-of select="name()"/>
        </td>
    </xsl:template>
</xsl:transform>

mdawoodk · #9 (**permalink**) March 14th, 2005, 05:55 AM

instead of all the tag names of mags/mag. Is it possible to get the child tag names of first "mag"?

Need to download code?

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