Hey cant u write ur own funtion for this simple problem? Anyway i shall state the same for u.

1. U can use the floor function to get the integral part of the decimal number. i.e on ur

VB.NET IDE type math.floor(UrDecimalNumber)

Eg.. Math.Floor(5.6) would yeild 5 as the result.

2. Then subtract this integral part that u get from the decimal number. This would give u the decimal part that u require.

Eg. 5.6 - 5 = 0.6 (Required Result)

It is not how much we do,

but how much love we put in the doing.

-Mother Theresa