Input XML:
-----------
<OUT>
<OUT_ITEM>
<ITEM_ID>151844</ITEM_ID>
</OUT_ITEM>
<OUT_ITEM>
<ITEM_ID>151845</ITEM_ID>
</OUT_ITEM>
<OUT_ITEM>
<ITEM_ID>151846</ITEM_ID>
</OUT_ITEM>
</OUT>

Expected Output:
----------------
<?xml version = '1.0' encoding = 'UTF-8'?>
<ILResponse>
<DA>
<Revision>
<Number>1</Number>
</Revision>
</DA>
<DA>
<Revision>
<Number>2</Number>
</Revision>
</DA>
<DA>
<Revision>
<Number>3</Number>
</Revision>
</DA>
</ILResponse>

XSL tried code:
---------------
<xsl:template match="/">
<ILResponse>
<xsl:for-each select="OUT/OUT_ITEM">
<DA>
<xsl:variable name="ItemIndex" select="0"/>
<xsl:variable name="ItemIndex1" select="$ItemIndex+1"/>
<Revision>
<Number>
<xsl:value-of select="$ItemIndex1"/>
</Number>
</Revision>
</DA>
</xsl:for-each>
</ILResponse>
</xsl:template>

I want to increment the variable for the no of times the OUT_ITEM are there in the input XML. My goal is to maintain the index value. please suggest. Found that every time the initial value of the variable is returned.

You cannot update variables in XSLT, therefore you cannot increment a variable in the way you are asking to.

In the scenario you mention above I suspect you can just use the position() function which will return the position of the current item in matching the template.

<xsl:value-of select="position()"/>

__________________
/- Sam Judson : Wrox Technical Editor -/

Hi samjudson thanks for the reply. No actual my requirement is different. This is a sample template which i posted for letting my requirement. I want to update the variable each time which is not possible in xslt. Actually i will be getting the xsl from other xml file where i want to traverse based on the index value Ex: <Revision><Number><xsl:value-of select="$OtherSource[1]"/></Number></Revision>. Let me try it through XPath. Thank you

Same answer:

<Revision><Number><xsl:value-of select="$OtherSource[position()]"/></Number></Revision>

__________________
/- Sam Judson : Wrox Technical Editor -/

>Same answer:

<Revision><Number><xsl:value-of select="$OtherSource[position()]"/></Number></Revision>

Umm, no: it needs to be

<Revision><Number><xsl:variable name="pos" select="position()"/><xsl:value-of select="$OtherSource[$pos]"/></Number></Revision>

because position() changes its value inside a predicate.

__________________
Michael Kay
http://www.saxonica.com/
Author, XSLT 2.0 and XPath 2.0 Programmer\'s Reference

Hi samjudson thank you. The position() function works in this use case i have given but not in my actual case. Thank you. I am able to achieve using the XPath. It always returns 1 in my actual case.

Thanks Michael yes you are right if we initialize through a variable and then pass it works.