Sorry, I found it faster than the posts again:

From the MS Scripting Center:

InStr Function Example
This example uses the InStr function to return the position of the first occurrence of one string within another.

Dim SearchString, SearchChar, MyPos
SearchString ="XXpXXpXXPXXP" ' String to search in.
SearchChar = "P" ' Search for "P".

' A textual comparison starting at position 4. Returns 6.
MyPos = Instr(4, SearchString, SearchChar, 1)

' A binary comparison starting at position 1. Returns 9.
MyPos = Instr(1, SearchString, SearchChar, 0)

' Comparison is binary by default (last argument is omitted).
MyPos = Instr(SearchString, SearchChar) ' Returns 9.

MyPos = Instr(1, SearchString, "W") ' Returns 0.

I had the syntax backwards.

It is "strYes = InStr(strMessage, strApp)"
Not "strYes = InStr(strApp, strMessage)"




mmcdonal