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Apache Tomcat General discussion of the Apache Tomcat servlet container. For discussions specific to the Professional Apache Tomcat book, please see the book discussion forum for that book.
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Old September 18th, 2004, 09:28 PM
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Default Tomcat; Am I doing it wrong?

Hi, I just bought the book Prof. Java Servlets 2.3 and using Tomcat 5.0 on it.
The first example in the book tells me to make a directory in the webapps directory of tomcat

servletAPI WEB-INF classes basicServlets src basiicServlets
now putting the class file in the servletAPI\classes\basicServlet directory i access the page using http:\\localhost:8080\servletAPI\servlet\basicServ let.BasicServlet

but this doesn't work.

Anyways, the first example in the book which i compile successfully is here:

package basicServlets;

import javax.servlet.GenericServlet;
import javax.servlet.ServletConfig;
import javax.servlet.ServletRequest;
import javax.servlet.ServletResponse;
import javax.servlet.ServletException;
import java.io.IOException;
import java.io.PrintWriter;
import java.util.Date;

 * Title: Professional Java Servlet Programming - Chapter 2
 * Description: Basic servlet to demonstrate extending from GenericServlet
 * Copyright: Copyright (c) 2001
 * @author Andrew Harbourne-Thomas
 * @version 1.0
public class BasicServlet extends GenericServlet {
  private static int count = 0;
  private static final Date initialDate = new Date();
  private Date thisDate;

   * Initialize global variables, special resources such as Database
   * connections etc.
  public void init(ServletConfig config) throws ServletException {
    thisDate = new Date();
    //System.out.println("BasicServlet initialized at:" + thisDate);
    log("BasicServlet initialized at:" + thisDate);

   * Here we simply output a very simple HTML page
   * @param request The object containing the client request
   * @param response The object used to send the response back
  public void service(ServletRequest request, ServletResponse response)
    throws ServletException, IOException {
    //access the PrintWriter object of the response object
    //to respond the request
    PrintWriter out = response.getWriter();

    //Simple HTML page
    out.println("<body><h2>" + getServletName() + "</h2>");
    out.println("This is a basic servlet.<br>");
    out.println("<tr><td><b>BasicServlet executed:</b></td><td>" +
                  (++count) + " time(s)</td></tr>");
    out.println("<tr><td><b>BasicServlet initialized at:</b></td><td>" +
                  initialDate + "</td></tr>");
    out.println("<tr><td><b>This instance initialized at:</b></td><td>" +
                  thisDate + "</td></tr>");
    out.println("<tr><td><b>Current Time:</b></td><td>" +
                  new Date() + "</td></tr>");
    out.println("<tr><td><b>Servlet Information:</b></td><td>" +
                  getServletInfo() + "</td></tr></body></html>");

   * Overridden to give Servlet information
  public String getServletInfo() {
    return "basicServlets.BasicServlet; Version: 1.0; (C) 2002.";

   * Clean up resources
  public void destroy() {
    //System.out.println("BasicServlet: destroy method called");
    log("destroy method called");
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Old September 19th, 2004, 03:33 PM
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What happens when you try to open the url?

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Old September 20th, 2004, 02:29 AM
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What is the Error Message !!!

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Old September 13th, 2005, 09:41 AM
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have you created your web.xml file and placed it in WEB-INF?

another option to run the servlet if you don't know how to create the web.xml yet is to place the BasicServlet compiled class in the directory:
and start your tomcat and run the servlet
Note: take the (package basicServlets) off your code

if you to choose to put the class in basicServlet package

hope this help

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