Hello

What i want to do is display a grid from a table, however if there is data in a text field then i want to display an icon or hyperlink which takes the user to another form to view the contents of the field otherwise the column is blank.

Regards

Guy

First create a Hyperlink column, or template column with a Hyperlink or icon.
Then use the ItemDataBound event of the grid. Check the column in question there. If data exists show the hyperlink, otherwise set the Visible property to FALSE.

Thanks for replying so quickly.

I have added a hyperlink to my grid, this is the actual code

<asp:HyperLinkColumn HeaderText="Details" DataNavigateUrlField="details0"
Text="<img src='images/view.gif' border='0'>"
DataNavigateUrlFormatString="javascript:varwin=win dow.open('Log_Details.aspx?detail={0}', null, 'top=400, left=400, width=600, height=250');"></asp:HyperLinkColumn>

I just have two questions
In the ItemDataBound event i check that we are looking at data row
(not header or footer) but am not sure how to reference the actual column to make it visible

Secondly
if the user clicks on the gif, i want to open a popup with some text
which it seems to work ok. But when the popup opens on the bottom of the form, the calling form which has the grid on it blanks out and only the tag [Object] is visible.

Any ideas what i am doing wrong????

Thanks

Guy

1. You need to know index of the column you want. The index is 0 based. So if the 4th column is the one you want, the index is 5. Ex:

Dim hl As New HyperLink
hl1 = CType(e.Item.Cells(HyperLink Column Index).Controls(0), HyperLink)
If CInt(e.Item.Cells(Your Column Index).Text) = "" Then
   hl.Visible = False
End If

2. I am not sure why that is happening. Try tracing through your code to see if you can find the problem.

Jim