Hi all,

I am using regular expression validator for validating number upto 2 decimal places. I am using following following regular expression for validation.

\d{1,3}.\d{0,2}

This works fine for numbers like 1.23 or 1.00. But if I enter 1 or any integer, the expression is not accepting it.

I want regular expression which will accept interger input as well as number upto 2 decimal places.

Please help.

Make the second part of your RegEx conditional.

"The one language all programmers understand is profanity."

Will you please tell me how to make it conditional?

Hi,

You can make second part optional if your second part preceeds by a question mark "?".

^\d{1,3}(\.\d{0,2})?$

Best Regards,
Amit Chawla.