Okay, I have a regular expression to check for a numeric data type that looks as (\d{1,}). Is there a way to incorporate into this expression to allow whitespaces in between the numbers?

How about [0-9 ]+ (i.e. replace the \d with 0-9 and then add a space character. Also, + is equivalent to {1,})

You could also do (\d+\w+)+ which will check for a number (or group of numbers), then for whitespace, then repeats over and over again.

but this does not accept 0.00 as numeric value or it does not accept "."(decimal point) as numeric value. What is the best solution? How can I write such regular expression

Bharat Gadhia
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Bharat Gadhia

I don't know if the \d includes decimal points. It may, but I don't know. You'll have to check that out.

If decimal points need to be included (and the \d doesn't cover it), but also spaces are required between numbers, you could do:

(\d+(\.\d+)?\s+)+

I realize one error on my part previously; I used a \w instead of \s; \w doesn't contain spaces.

This allows for:
<many digits to the left>.<many digits to the right><many spaces>

For one space change \s+ to \s
For multiple decimal points (or possibly none) change (\.\d+)? to (\.\d+)*