In my application I have used a Web User control . Inside the form I have a dropdown field.A pop up window will display , based on the option selected from the dropdown.

for my dropdown selected index changed I have

string strJavascript = "window.open(\"intDisplay.aspx\", \"gointl\", \"height=500,width=600,scrollbars=yes,resizable\") ;";
ScriptManager.RegisterStartupScript(this, this.GetType (), "OpenWindow", strJavascript, true);

But the popup window is not showing up. I have used Update Panel in my form.

PLease let me know some suggestions. Thanks,

hi there.. where do you have the update panel...

HTH

Gonzalo

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The whole form is inside the update panel.

try to add this paramater to your jave script "'_new'"


:)


Nothing is impossible. The impossible only takes longer. "Digital Fortress, Dan Brown"

I have the same prob. where should I add this Java script parameter "'_new'"

function ShowRegistration()
    {
        window.showModalDialog("SellerRegisterProductPopUp .aspx?Key=" + '<%=strProductId%>',"","dialogWidth:350px; dialogHeight:200px; center:yes; resizable:no");
        return false;
    }

I'm calling this fuction on some condition from code behind file. If condition stisfies RegisterForm is shown otherwise not with help of code as -

Page.ClientScript.RegisterStartupScript(this.GetTy pe(), "showAl", "ShowRegistration();", true);

try something like this

Response.Write("<script>window.open('temp.aspx','_ new');</script>");

Nothing is impossible. The impossible only takes longer. "Digital Fortress, Dan Brown"