I am trying to get a window to open when someone clicks a link. The link is created using a Response.Write. It works if I use something like this:

But as soon as I put a file in there (what I am really trying to open in a new window), it wont work. Here is what I am doing for that:

I have turned off Pop Up blocker, done everything I can think of, but it just doesn't open. I get no errors as to why, either. Anyone have an idea as to why the second one won't open but the first will?

edit: I can also Right Click -> Copy URL and paste it into a new tab and have it work that way as well. So the href is correct, it just doesn't open when you click it...

Where does this code run?

'file:///" + location + "OutputReports\\xmlTrans" + tick + ".html'

file:// runs on the client; not the server. So, something like

file://c:\SomeFile.txt would be searched for at the client, not the server.....


Imar


---------------------------------------
Imar Spaanjaars
http://Imar.Spaanjaars.Com
Everyone is unique, except for me.
Author of Beginning ASP.NET 3.5 : in C# and VB, ASP.NET 2.0 Instant Results and Dreamweaver MX 2004
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The code writes the links to the pages, it isn't actually executing it from the server. It's meant for the client to click the link. And we got it working; I had the right idea, just wrong syntax. We changed it from "location+'\\OutputReports........" to just "~/OutputReports..." and that's what did it. Stupid little things like that piss me off :P

...which reinforces what Imar said. The ~ character evaluates a path that exists on the SERVER whereas file:// evaluates a path on the CLIENT.

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first u need to evaluate why u want to use "'file:///"
If u are planning to open a file which is not stored on a webserver (localhost or any site on other than 8080/80port), then u can not open that HTML file.
Instead what u can do is that
if the file is located on the file system, then u can give the neccessary rights to the directory on the machine and read the file using FileSystem object and throw all the content on the newly opened window. But for that u will need an intermediate page which will take the input as the fileName.

I am sorry if this is not what you are looking for... From your Code I wrote what I understood.


D.