This is the code for menu2.php

<?php

$Desserts=array("Apple Pie ($3)","Pancakes ($3)","Ice Cream ($2)");

echo "<FORM METHOD=POST ACTION='bill.php'>";
echo "Which of the following would you like as a dessert?";
echo "<SELECT NAME='ListBox2'>";
echo "<OPTION SELECTED VALUE=''>Select...</OPTION>";
echo "<OPTION>$Desserts[0]</OPTION>";
echo "<OPTION>$Desserts[1]</OPTION>";
echo "<OPTION>$Desserts[2]</OPTION>";

echo "</SELECT><BR><BR>";
echo "<INPUT TYPE=HIDDEN NAME=Course1 VALUE='$ListBox1'>";
echo "<INPUT TYPE=SUBMIT>";
echo "</FORM>";
?>

I don't understand where the value for variable $ListBox1 come from? It's like it appear by itself. I do understand that there ia value named 'ListBox1' (not a variable) passed from menu1.php. But in menu2.php, there is no value assigned to the variable $ListBox1 at all. I thought there is another code needed for menu2.php like $ListBox1 = $_POST['ListBox1']; Then the variable $ListBox2 has a value now. I am really confused. I really appreciate if someone can help me out here.

Though I am not sure I think that
you are in form no. 2; previously you have submitted another form. and here $ListBox1 variable contains the value that passed from previous page.

I think, before PHP 4.1 we use the variable name directly to retrieve any value, that passed with the URL.

But after PHP 4.1 we use $_POST['variable'].

thanks

Best Regard:
Md. Zakir Hossain (Raju)
Webmaster
www.rubd.net