Hi,
What you need to do is make a select query that selects a record from a table.
In that table on of the fields must have a image Url(You can't store an image into a mysql database).
so your query would look something like the following
Code:
Select image_url from images where image_id=1;
when you have retrieved the url its just a matter of doing a echo like:
Code:
echo("<img src=\"".$imageUrl."\" />)
hope that helped
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