parse error in php

ravi951 · September 21st, 2011, 01:18 AM

hi all,
i have written a code using php for sessions.it will checks whether the
user is new or already registered...
i am getting the error as
Parse error: syntax error, unexpected T_ELSE in C:\xampp\htdocs\shopping1\task.php on line 16
kindly tell me what went wrong.
below is the code......

Code:

<?php
define("LIMIT", 10);
session_start();
//connect to database
$db = mysql_connect("localhost","root","") or die(mysql_error());
mysql_select_db("shopping", $db) or die(mysql_error());
$islogged = FALSE;
if(!isset($_SESSION["last_activity"]) || time() - $_SESSION["last_activity"] > LIMIT ) 
  {
    session_destroy();
    header("Location:logout.php");
  }
  $_SESSION["last_activity"] = time();
  $islogged = TRUE;

else 
{
if(isset($_POST["username"]) && isset($_POST["password"])) 
{
$result = mysql_query("SELECT * FROM login WHERE `username` = '$_POST["username"]' AND `password` = '$_POST["password"]'");
if(!$result) die( mysql_error());
  if(mysql_num_rows($result)) 
  {
   $_SESSION["last_activity"] = time();
   header("Location:products.php");
   $islogged = TRUE;
  }
  else 
  {
   $error = "username and password do not match";
  }
}
}
?>

<?php if(!$islogged): ?>
<form action="<?php $_SERVER['HTTP_REQUEST']?>" method="POST">
<?php if( isset($error) ): ?>
<p><?php echo $error;?></p>
<?php endif; ?>
Username:<input type="text" name="username" value="<?php isset($_POST['username']) ? $_POST['username'] : ''?>"
</br>
Password:<input type="password" name="password" value="<?php isset($_POST['password']) ? $_POST['password'] : ''?>"
</br>
<input type="submit" name="login" value="log in">
</form>
<?php endif; ?>

GeneBuchite · September 21st, 2011, 09:25 AM

The code

Code:

   $_SESSION["last_activity"] = time();
  $islogged = TRUE;

Should be moved. Looks Like you could close the if statement after the above code... ie..

Code:

 <?php
define("LIMIT", 10);
session_start();
//connect to database
$db = mysql_connect("localhost","root","") or die(mysql_error());
mysql_select_db("shopping", $db) or die(mysql_error());
$islogged = FALSE;
if(!isset($_SESSION["last_activity"]) || time() - $_SESSION["last_activity"] > LIMIT ) 
  {
    session_destroy();
    header("Location:logout.php");
  
  $_SESSION["last_activity"] = time();
  $islogged = TRUE;
}
else 
{

ravi951 · September 21st, 2011, 09:29 AM

first i need to check whether session exists or not.
if not exists then using the time function i need to store that using session id
else if exists then no need of creating time function
how yto modify in the above code so that it will work like above said.......