Hello,

byte data is declared and initialized to 1

 How should I read the following line: data *= 2; // Multiply by 2. Can this be translated 1*2=2(1x2=2)? Second line below meaning 2*2=4?
I don't understand how data *=2 should be translated and/or read.


Thanks

//Chapter 2, Exercise 1
public class ByteTest { // Ensure classes/variables have distinctive names.
public static void main(String args[]) {
    // Initialize variable data of type byte to 1:
    byte data = 1;

    data *= 2; // Multiply by 2
    data *= 2; // Multiply by 2: 1st time data is equal to 1 times two equals two
    System.out.println("data = " + data);
    data *= 2; // Multiply by 2: 2nd time
    System.out.println("data = " + data);
    data *= 2; // Multiply by 2: 3rd time
    System.out.println("data = " + data);
    data *= 2; // Multiply by 2: 4th time
    System.out.println("data = " + data);
    data *= 2; // Multiply by 2: 5th time
    System.out.println("data = " + data);
    data *= 2; // Multiply by 2: 6th time
    System.out.println("data = " + data);
    data *= 2; // Multiply by 2: 7th time
    System.out.println("data = " + data);

I think I've figureed this out.
It has to do with: The op=Operators.
byte data is declared and initialized to 1
data *=2 is the same as data = data *2
So the Byte data with value of 1*2=2.
So the consequent succession in code above doubles
(viz 1*2,2*2,2*4,2*8)

Where's my "Edit" gone?????
(My login was confirmed, but later not recognized)

(Wed. 12/3/03) Thank you


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