At the beginning, a and b are int. But finally, due to the use of pow (x, y) and in order to enhance the calculator, a and b become double. Just a little problem: why do they also become const ? They were not const at the beginning.

I have read the whole man pages of scanf, printf, and pow, and even looked at math.h, stdio.h and stdlib.h. I feel a little stupid and I really hope to get an explanation.

FJ

__________________
FJ

At this time, I had 139 readers. But none answered my question. In spite of this, I tryed to obtain information, and from Paris Apple Expo's developers present I got this: if processor type is not specified, double is 32 bits aligned because it is 64 bits sized. The way to manipulate double without specify processor type is to manipulate it as const double.

I am not sure I have really well understood, so if anybody would confirm, I would be grateful!

FJ

First, let me apologize for taking so long to reply

Second, the introduction of "const" in the solution for this exercise isn't a required part of the solution. Careful programmers use "const" in this context to tell the compiler these incoming values should not be modified. I probably added them as a reflex; they need not be const, and the example should probably just use "double a, double b".

Really, thank you! The explanation obtained in Paris "Apple Expo" was not very satisfactory.

FJ