chapter 7 check_image.php

hozdaman · October 13th, 2010, 10:18 AM

Hi,

Can someone help me with this. This is the try this code on page 179. I keep getting a parse error for the if statement and I can't figure out the error. Thanks

error
Parse error: syntax error, unexpected T_IF in /home/content/h/u/z/huzsak/html/admin/check_image.php on line 19

code

PHP Code:


			
//change this path to match your images directory



$dir='http://www.admin.pctoolmanconsulting.com/images'



//make sure the uploaded file tranfer was succesful

if ($_FILES['uploadfile']['error'] !=UPLOAD_ERR_OK)  {

    switch ($_FILES['uploadfile']['error'])  {

    case UPLOAD_ERR_INI_SIZE:

        die('The uploaded file exceeds the upload_max_filesize directive '. 'in php.ini.');

        break;

    case UPLOAD_ERR_FORM_SIZE:

        die('The uploaded file exceed the MAX_FILE_SIZE directive that ' . 'was specified in the HTML form.');

        break;

    case UPLOAD_ERR_PARTIAL:

        die('The uploaded file waas only partially uploaded.');

        break;

    case UPLOAD_ERR_NO_FILE:

        die('No file was uploaded');

        break;

    case UPLOAD_ERR_NO_TMP_DIR:

        die('The server is missing a temporary folder.');

        break;

    case UPLOAD_ERR_CANT_WRITE:

        die('The server failed to write the uploaded file to the disk.');

        break;

    case UPLOAD_ERR_EXTENSION:

        die('File upload stopped by extension.');

        break;

    }

}



//get information about the image being uploaded

$image_caption = $_POST['caption'];

$image_username = $_POST['username'];

$image_date = date('Y-m-d');

list($width, $height, $type, $attr) = getimagesize($_FILES['uploadfile']['tmp_name']);



//make sure uploaded file is really a supported image

switch ($type) {

case IMAGETYPE_GIF:

    $image = imagecreatefromgif($_FILES['uploadfile']['tmp_name']) or

        die('The file you uploaded was not a supported filetype.');

    $ext = '.gif';

    break;

case IMAGETYPE_JPEG:

    $image = imagecreatefromjpeg($_FILES['uploadfile']['tmp_name']) or

        die('The file you uploaded was not a supported filetype.');

    $ext = '.jpg';

    break;

case IMAGETYPE_PNG

    $image = imagecreatefrompng($_FILES['uploadfile']['tmp_name']) or

        die('The file you uploaded was not a supported filetype');

    $ext = '.png';

    break;

default:

    die('The file you uploaded was not a supported filetype');

}



//insert information into image table

$query = 'INSERT INTO images

    (image_caption, image_username, image_date)

VALUES

    ("' . $image_option . '", "' . $image_username . '", "' . $image_date . '")';

$results=mysql_query($query) or  die (mysql_error());



//retrieve the image_id that MYSQL generated automatically when we inserted

//the new record

$last_id = mysql_insert_id();



//because the is is unique. we can use it as the image name as well to make

//sure we dont overwrite another image that already exists

$imagename = $last_id . $ext;



//update the image table now that the final filename is known.

$query = 'UPDATE images

    SET image_filename = "' . $imagename . '"

    WHERE image_id = ' . $last_id;

$results=mysql_query($query) or die (mysql_error());



//save the image to its final destination

switch ($type) {

case IMAGETYPE_GIF:

    imagegif($image, $dir . '/' . $imagename);

    break;

case IMAGETYPE_JPEG

    imagejpeg($image, $dir . '/' . $imagename, 100);

    break

case IMGAGETYPE_PNG

    imagepng($image, $dir . '/' . $imagename);

    break;

)

imagedestroy($image);

?>



<html>

  <head>

    <title>Here is your pic!</title>

  </head>

  <body>

    <h1>So how does it feel to be famous?</h1>

    <p>Here is the picture you just uploaded to our servers:</p>

      <img src="images/<?php echo $imagename; ?>" style="float:left;">

    <table>

      <tr><td>Image Save as: </td><td><?php echo $imagename; ?></td></tr>

      <tr><td>Image Type:</td><td><?php echo $ext; ?></td></tr>

      <tr><td>Height: </td><td><?php echo $height; ?></td></tr>

      <tr><td>Width: </td><td><?php echo $width; ?></td></tr>

      <tr><td>Upload Date: </td><td><?php echo $image_date; ?></td></tr>

    </table>

  </body>

</html>

tobimichigan · December 24th, 2010, 05:02 AM

If it is an unexpected "If" then check the program flow of an unended "if" or an "if" without a reason. This is a common parse error with a wrongly used code "selection".

Besides, the code on this particular script in chapter 07 has a number of errata. As it does not run as such..so you really have to do some serious modification on it b4 it gives the proper output.