Hi all,
i have been learning the photo gallery script in ch.7 and was wondering if anyone could help with this:

while ($rows = mysql_fetch_array($getpic)) {
 extract($rows);
 echo "<tr>\n";
 echo "<td align=center><a href=\"".$ImageDir . $image_id . ".jpg\">";
 echo "<img src=\"".$ImageThumb . $image_id . ".jpg\" border=\"0\">";

instead of calling the .jpg, i would like to call an html formatted page with the .jpg embedded into it. if anyone knows a simple way to do this, please help a php noob out :)
thanks

pass the image details to the URL and then using a new php file
eg.
echo "<td align=center><a href=\"pageyouwant.php?image=".$image_id.">";
 echo "<img src=\"".$ImageThumb . $image_id . ".jpg\" border=\"0\">";

then you will have a php file called pageyouwant.php

and the first thing is
$image_id = $_GET['image_id'];
use this then to create a new page showing your image
eg
echo "<img src=\"images/".$image_id."jpg\">";

hope it helped and made sense
RIchard