Hello,
I'm trying this since a week and am not able to get the result. Would appreciate if anyone would help me out with this one.

The given input is in the form 123-45-6789

Using regular expressions i want to extract 123456789 wihout "-"s.

I used the belwo RE
(?(\w[A-Za-z]*))\d{3}\-\d{2}\-\d{4}

It returns 123-45-6789

Can any one suggest me a way to extract only the nine digits without the hypens.

Thank You very much.

Can anyone please help mw out with the above.
Thanks

Hi,

This will return you the three groups without hyphens:
(\d{3})-(\d{2})-(\d{4})

It will not do output formatting, because that's not what regex is meant for... so you will have to stick the pieces together yourself in the software you are writing, with a replace function...

Hi Mak,

 I'm master of Perl regex. :-)
 This simple program explain, how to extract first sequense of exact nine digits from a string.
The found nine digits are not preceded or followed any digit.
 Sorry for my English (I studied German).

#!/usr/bin/perl -w
use strict;

my $s='012-34-56789 123-45-6789 012-34-5678';
my $result;
our $temp;
print "$result\n" if $s =~ /(?{local $temp=''})(?<!\d)(\d(?{$temp.=chr vec($s,pos($s)-1,8)})-?){9}(?![\d-])(?{$result=$temp})/;

# Output: 123456789


Regards,
Serge
http://www.gameintellect.com

Hi,

could u please help!!

I need regexp to match the string:

0123456789_abc_abc.xml

where as: _abc is optional.

My reg exp looks like:
String regExp = "^\\d{10}(_\\d)?(_\\d)?\\.xml$";

But it does not work correctly, any ideas please??

Thx

Simon