Hi! I don't understand pages 181,182,183.

Especially the section that says:
"Compared to using a ‘normal’ array, the pointer array normally carries less overhead in terms of space. With an array, you would need to make each row the length of the longest string, and six rows of seventeen bytes each is 102 bytes, so by using a pointer array you have saved a whole -1 bytes!"

Why I have saved 1 byte?

Figure 4-7 shows that in the case of the pointer array I am using 103 bytes. I don't understand why 24 bytes are allocated for the pointer array?

In pg. 182 in 3rd paragraph it is mentioned that "With the pointer array as above you just need to swap the pointers". How do I do that?

Thanks

It's -1 byte In the normal array if you set the length of the longest string Hopalong Cassidy\0 17 bytes then each string would be 17 times 6 which is 102 bytes. In the pointer array if you count all the bytes in the strings would be 79. Each pointer would require 4 bytes to hold the address of the string therefore 24 bytes are used by pointers bringing the total byte count to 103.

To swap the pointers just change the names of the pointers
char* pstr1 = "Robert Redford"
char* pstr2 = "Hopalong Cassidy"
change to
char* pstr2 = "Robert Redford"
char* pstr1 = "Hopalong Cassidy"