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BOOK: PHP and MySQL 24-Hour Trainer
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Old April 4th, 2012, 11:31 AM
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Question to recover "undefined variable" error

<title>Movie Details</title>
  function get_director()
	  global $movie_director;
	  global $director;
	  $query_d=mysql_query("SELECT full_name FROM people WHERE id='$movie_director' ");
	function get_leadactor()
	  global $movie_leadactor;
	  global $leadactor;
	  $query_a=mysql_query("SELECT full_name FROM people WHERE id='$movie_director' ");
  function calculate_difference($takings,$cost)
		   $difference= substr($difference,1);
		  $profit_or_loss='Broke even';

          return "<font color='$font_color'>".$profit_or_loss."</font>";
		 $result=mysql_query("SELECT * FROM movie WHERE id='".$_GET['movie_id']."'");
			$movie_director=$rows ['movie_director'];
			$movie_leadactor=$rows ['movie_leadactor'];
			$movie_year=$rows ['movie_year'];
			$movie_running_time=$rows ['movie_running_time'];
            $movie_taking=$rows ['movie_taking'];
			$movie_cost=$rows ['movie_cost'];

		 <tr> <h2><center><?php echo  "$movie_name:details"; ?></center></h2>	</tr>
		 <table width='70%' border='0' cellpadding='2' cellspacing='2' align='center'>
		 <th>Movie Title</th>
		  <th>Year Of Release</th>
		  <th>Movie Director</th>
		  <th>Movie Lead Actor</th>
		  <th>Movie Running Time</th>
		  <th>Movie Health</th>
		   <td><?php echo $movie_name;?></td>
		   <td><?php echo $movie_year;?></td>
		   <td><?php echo $director;?></td>
		   <td><?php echo $leadactor;?></td>
		   <td><?php echo $movie_running_time;?></td>
		   <td><?php echo $calculate_difference;?></td>
.....problem is, after i run this code there showing an error such as "Notice: Undefined variable: movie_takings in G:\wamp\www\RED BOOK PRACTISE\movie_details.php on line 94
Call Stack" not only the $movie_takinng ,the same error is showing including the other variables separately....can i have solution plzzz...

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