need help with a program

captlem66 · #1 (**permalink**) October 12th, 2004, 09:50 PM

I need help in writing a program that gives the roll of three different dice with numbers between 1 and 10 on them (two cant be the same number) then give the total of the three and ask if the next roll will be higher and lower. If they guess correct the game will keep going if not the game will end and give how many rounds they went and the probability they would get that far. Can anyone help me I know very little about programming and would greatly appreciate any help

mehdi62b · #2 (**permalink**) October 13th, 2004, 02:52 AM

Hi captlem66,

Quote:

quote:Originally posted by captlem66
if not the game will end and give how many rounds they went and the probability they would get that far

I think the hardest step in your problem is to get the probability,
I think you should solve this,
the numbers of answers that the below equation could accept,
dice1+dice2+dice3<PreviousStep(if it is lower)
dice1+dice2+dice3>=PreviousStep(if it is higher)
PreviousStep is the total of three numbers on dices from the previous step and also 1<=dice1<=10 and 1<=dice2<=10 and 1<=dice3<=10 and also dice1!=dice2!=dice3....
I have some problem with the last statement(dice1!=dice2!=dice3)if they could also be the same(like the real world)I can solve this problem ....
maybe your meaning from getting the probability is something else ...
Did I guess your meaning correctly?

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Mehdi.:)

mehdi62b · #3 (**permalink**) October 16th, 2004, 12:05 PM

ohh,sorry,I was just thinking I'm taking mathematics exam!!!
I forgot we have a computer and can use it!!!

Code:

a special syntax!!!
int sum:=0;
int pre=:PreviousStep;
For Dice1:=1 to 10
 For Dice2:=1 to 10
  For Dice3:=1 to 10
     if(dice1!=dice2!=dice3) & (dice1+dice2+dice3>=Pre)  then sum:=sum+1;
//sum is the naswer

now the probability is n(A)/n(S);
n(S)=10*9*8
n(A)=sum
so p(A)=n(A)/n(S)=sum/10*9*8.

--------------------------------------------
Mehdi.:)