I have need to program on a cross-platform basis. I am coding on Windows/OSX/Linux, unfortunately the size of certain data types can vary between these OS's and compilers.

I have found a way to ensure the size of the datatypes on Windows: __intn and on OSX: uintn/sintn, but I am wondering if there is a ISO standard size defined numeric type?

Thanks for your time,
Miq

use sizeof method
int i=0;
cout<<sizeof i<<endl;
there is no ISO standard.

should be
....sizeof(i)....

Alan

no sir,
it's --> sizeof i

sizeof() is a function (not a method) and needs the brackets to hold the argument i.

If you omit the brackets it will compile but the output will not show the size of the integer.

Please post the code of a program you have written and got to run showing the correct output with sizeof used as you say.

Alan

No,sizeof is a operator,not function or method
you can use like that:
1) sizeof( object );
2) sizeof( type_name );
3) sizeof object; //

We can use the sizeof operator in the ways described by phoenix.

The only thing we must remember is to put an extra space after sizeof.
For example, if we use:
sizeof i
then it will return the size of i.
But if we use it as:
sizeofi
then only an error message will pop up saying that
sizeofi undeclared.

Regards,
Paramesh.

"Don't walk behind me; I may not lead.
 Don't walk in front of me; I may not follow.
 Just walk beside me and be my friend."

sizeof is an OPERATOR:
Here is the heading from a well known tutorial on C++:
"SIZE OF - AN OPERATOR BY ITSELF . . . sizeof is an operator, not a function. If you apply it to a type, it must be used with the parenthesized form, but if you apply it to a variable you can use it without parentheses . . ."