hai

We have two variables X,Y
and say X = 8;
        Y = 5;
Now how can you interchange values of these variables?
with out using third variable
 i.e Z = X; X = Y; y = z;
or any function
 i.e interchange(X,Y).
This can be achieved by simple mathematical mathod.

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A little more effective way:

int a = 2;
int b = 3;

a += b; // a = a + b -> a = 5
b = a; // -> b = 2
a -= b; // a = a - b -> a = 3

Ok

hai iut.aristo you are correct.

hai RoBoT
yours should be like this

    a = a + b
    b = a - b
    a = a - b .

and one long method also

    x = e^(x+y)
    y = x/e^y
    x = x/y
    x = ln x
    y = ln y ( 5 steps using logarithms )

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http://www.amsterdamhotels.at/
http://www.indianhillresorts.info/
http://www.cheapparishotels.info

another interesting way from Ivor Horton's book:

    The ^ operator has a surprising property.
    Suppose that you have two char variables, "first" with
    the value ‘A’, and "last" with the value ‘Z’,
    corresponding to binary values "0100 0001" and "0101 1010". If
    you write the statements

    first ^= last; // Result first is 0001 1011
    last ^= first; // Result last is 0100 0001
    first ^= last; // Result first is 0101 1010

    the result of these is that "first" and "last" have exchanged
    values without using any intermediate memory
    location.This works with any integer values.

Hi
Here is the code

a=(a+b)-(b=a);

and here is another one


a = ( a * b ) / ( b = a );

and now, another short code fragment:

    x = ln ( ( e ^ ( x + y ) ) / ( e ^ ( y = x ) ) )

Ups ... working kills the brain, sorry