i'm a beginner in c field, and i meet a problem i can't understand why and how to occur that.
my code as follow:
#include <iostream.h>
#include <stdio.h>
void main()
{
 int a;
 scanf("%d\n", &a);
 printf("wut u get from the console is: %d", a);
}

when i add '\n' in scanf function as you see before, it can't work as i hope. why? and how? thanx!

Hi,

what do you expect to see if you haven't initialised the variable "a".
what you need to do to see anything is initialise "a".

Hope this helps.
wambozi.

I hope you are kidding (wambozi) do you know what is scanf function?
I think you don't, but you will learn some day I hope.

Here is your answer vincentaries, you are declaring "a" as int, but you are using: scanf("% "d" \n", &a); %d this is four double not for int so try this: scanf("%lf\n", &a); this shoud resolve you'r problem;)

PD. you can use the %lf and save it in double variable but not vise-verse.