Hello.

I have this simple program, but it won't take in letters as input. I know you use the char for letters, and int for numbers, just for an example.

Here is my program:

// Test program

#include <iostream>
using namespace std;

int main()

{

int hash = 0;

cout << endl

     << "Write the first letter or number: ";

cin >> hash;

cout << endl;


if(hash == 1)

    cout << endl

         <<"Write the second letter or number: ";

cin >> hash;

cout << endl;

{

if(hash == 'a')


       cout << "The first letter is a" << endl;

}


return 0;

}

So if the user first types 1, then afterwards types a, the program outputs: The first letter is a. The problem is that the program doesn't like the if(hash == 'a') part. When i run the program, and type in 1, and then when i type in the a, the program just ends, doesn't go any further. If i change the if(hash == 'a') to if(hash == 2) it works.

Hello.
   I don't think the problem is that the program doesn't like the if(hash == 'a') part.If you first types 1, then afterwards types 97,I think the program will like it.
   I think the reason is that cin refuse to give the value of char to a int number,but the '=' can.So when you input a char,cin give 0 to the int number and when we input 97,the value of "hash=='a'" is not zero,is true.We can use hash = 'a' to give hash a valid value,it's 97,but we can't use cin>>hash to do this.
  Try this:
  type 1.2,then see the value of hash is what.It's 1.
  The reason is that to float number,'=' and cin both convert it to a int number and give the result to hash.

  Clear?We can't use cin>>hash to give a char's value to hash,we can only use it to give a int number's value to hash.


niuwei