please help

kittysweetheart24 · May 31st, 2007, 06:34 PM

Hi!

I have made a button for the OpenFileDialog dialog control and it works fine. But when I select a file to open a file, nothing happens ... What code should I write to open some text files and also ppt files (Power Point Presentations)?

I know that myStream = openFileDialog1.OpenFile() but what should I do with the stream in order to open a selected file in Notepad, for example ? If u can, please send my some examples.

I'm a really beginner in C# and I need your help urgently..

Thanks

Kitty.

David_0223 · June 1st, 2007, 01:20 PM

Kitty,

You might try something like:

private void button1_Click(object sender, EventArgs e)
{
    openFileDialog1.Filter = "Text Files|*.txt";
    openFileDialog1.ShowDialog(this);
    Stream sr = openFileDialog1.OpenFile();

    byte[] buff = new byte[70];
    sr.Read(buff, 0, 60);

    System.Diagnostics.Debug.WriteLine(Encoding.ASCII. GetString(buff));
    sr.Close();
}

This does not take into account end of line or end of stream and just writes the output to the debuggin window.

Good Luck.

What you don't know can hurt you!

dafl00 · June 2nd, 2007, 01:52 AM

If you wanted to open notepad as an external application, you can do this:

Code:

private void button1_Click(object sender, EventArgs e)
{
    OpenFileDialog ofd = new OpenFileDialog();
    if (ofd.ShowDialog() == DialogResult.OK)
    {
        System.Diagnostics.Process.Start("notepad.exe", ofd.FileName);
    }
}