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Old May 31st, 2007, 06:34 PM
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Default please help


I have made a button for the OpenFileDialog dialog control and it works fine. But when I select a file to open a file, nothing happens ... What code should I write to open some text files and also ppt files (Power Point Presentations)?

I know that myStream = openFileDialog1.OpenFile() but what should I do with the stream in order to open a selected file in Notepad, for example ? If u can, please send my some examples.

I'm a really beginner in C# and I need your help urgently..


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Old June 1st, 2007, 01:20 PM
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You might try something like:

private void button1_Click(object sender, EventArgs e)
    openFileDialog1.Filter = "Text Files|*.txt";
    Stream sr = openFileDialog1.OpenFile();

    byte[] buff = new byte[70];
    sr.Read(buff, 0, 60);

    System.Diagnostics.Debug.WriteLine(Encoding.ASCII. GetString(buff));

This does not take into account end of line or end of stream and just writes the output to the debuggin window.

Good Luck.

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Old June 2nd, 2007, 01:52 AM
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If you wanted to open notepad as an external application, you can do this:
private void button1_Click(object sender, EventArgs e)
    OpenFileDialog ofd = new OpenFileDialog();
    if (ofd.ShowDialog() == DialogResult.OK)
        System.Diagnostics.Process.Start("notepad.exe", ofd.FileName);
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