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  #1 (permalink)  
Old February 4th, 2004, 04:17 PM
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Default HELP - C# newbie question on variables & propertie

I have a class that is access a webservice that contains the stored
procedure that I am accessing but I do not know how to apply variables to the elements of the dataset so that I can access it in my property.
ANY help or direction would be appreciated. Thanks.

[u]Here is my class code</u>:

public class InvoiceList
{
private int iintClientid = 0;
private int iintMonth = 0;
private int iintYear = 0;
private string istrFullName;
private DataSet idsInvoices;
private string dsReturnedData = "ClientInvoices";

// Constructor
public InvoiceList(int aintClientID, int aintMonthText, int aintYearText)
{
iintClientid = aintClientID;
iintMonth = aintMonthText;
iintYear = aintYearText;

// Connect to the PSSBilling_WebService.
PSSBilling.Service1 wsSearch = new PSSBilling.Service1();

// Define the dataset for this class.
idsInvoices = new DataSet();
idsInvoices = wsSearch.getInvoiceDataByClient( intClientid, iintMonth,
iintYear );

istrFullName =
Convert.ToString(idsInvoices.Tables["ClientInvoices"].Columns["full_name"].ColumnMapping["full_name"]);
Console.WriteLine(istrFullName);
}

[u]Here is my PROPERTY CODE</u>:

//Public Property created to EXPOSE the data elements for the INVOICE
FORM.

public string InvoiceFullName
{
get
{
return istrFullName; // THIS IS TELLING ME UNREACHABLE CODE
Console.WriteLine(istrFullName);
}
}
}
  #2 (permalink)  
Old February 4th, 2004, 07:14 PM
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Default

I can't see anything wrong with this. Can you post the exact error?
  #3 (permalink)  
Old February 4th, 2004, 07:27 PM
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Default

As soon as return is found in a method (in this case, the Get accessor for the InvoiceFullName property), the return value is returned, and execution of the method stops:
Code:
get
{
  return istrFullName;
  // THIS IS TELLING ME UNREACHABLE CODE
  Console.WriteLine(istrFullName);
}
As you can see, the Console.WriteLine call occurs after the return statement and is therefore unreachable. Swap the two statements and you should be fine:
Code:
get
{
  Console.WriteLine(istrFullName);
  return istrFullName;
}
Not sure about the other problems you're having though. Can you elaborate a bit?

Imar


---------------------------------------
Imar Spaanjaars
Everyone is unique, except for me.
  #4 (permalink)  
Old February 5th, 2004, 08:20 AM
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In my class, I am trying to verify the VALUE in this field called "Full_Name" but I am getting back the FIELD NAME, "Full_Name" not the value in it. Should I not see the value with the parameters I have setup for this variable = (istrFullName =
Convert.ToString(idsInvoices.Tables["ClientInvoices"].Columns["full_name"].ColumnMapping["full_name"]);
?

In my PROPERTY I get nothing back in the Console.Writeline command.

Thank you guys for your time and help. If you can lend any more suggestions they would be appreciated.
  #5 (permalink)  
Old February 5th, 2004, 10:02 AM
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A colleague of mine helped by stating that I had defined the ROW and that is why the value was not showing up. Here is what I did:

istrFullName = Convert.ToString(idsInvoices.Tables["ClientInvoices"].Rows[1]["full_name"]);

I did not realize I had to DEFINE the row that I was looking at.

Thank you guys again for your time and help. If you have any comments, suggestions or direction it would be appreciated.
  #6 (permalink)  
Old February 5th, 2004, 10:12 AM
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This code will return the name from the second row in the table in the dataset. The index are zero based, so Row[1] means the second row.

You can think of the Table in a DataSet like a normal table, or a spread sheet. It's divided in Rows and Columns:
Code:
DataTable myTable = idsInvoices.Tables["ClientInvoices"]

FullName = myTable.Rows[0]["FullName"].ToString() // returns FullName of first record
FullName = myTable.Rows[1]["FullName"].ToString() // returns FullName of second record
AnotherValue = myTable.Rows[0][0].ToString() // returns the first column for the first record
Take a look here: http://msdn.microsoft.com/library/de...gdatatable.asp and the articles around this one for more info.

Imar


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Imar Spaanjaars
Everyone is unique, except for me.
  #7 (permalink)  
Old February 6th, 2004, 03:52 PM
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Thanks for the help. It is appreciated.


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