Thanks for the replys, i have wasted your time it seems. The problem actually lay in that there was nothing unique about a record with 1 copy and a record with 3.
So Crystal couldnt distinguish when a book had 1 copy and when it 3 so, it would either:
a)Completly supress C.1's (Which is partially correct since anything with one copy shouldn't show this) and print C.2, C.3 etc...
b)Leave all the C.1's in (Which is not a good solution since books with 1 copy would show C.1) and print C.2, C.3 etc..
Thanks for reply though, i needed to learn about this statement anyway and your reply has cleared a lot up for me.
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