Could anyone please me with the below problem.

My input file for "argv[0]" is any sgm file
My output file is "ouput.xml"

For instance, if I pass my input file as "a003946.sgm", after all the necessary modifications, I need to rename my "ouput.xml" to "a003946.xml" without deleting my original input file.

Can anyone please me with the above problem.

My code is as below:



import java.io.*;
class browser
{
    public static void main(String argv[]) throws IOException{
        browser iop=new browser();
        int val;
        char ch;
        FileReader fr = new FileReader(argv[0]);
        FileWriter fw = new FileWriter("ouput.xml");
        while((val = fr.read()) != -1){
            ch = (char)val;
            if(ch == '<'){
                String str = "";
                while((val = fr.read()) != -1){
                    ch = (char)val;
                    if(ch == '>')
                        break;
                    else
                        str = str + ch;
                }
                if(str.startsWith("!DOCTYPE") == true)
                    fw.write("!DOCTYPE article SYSTEM \"entity.dtd\">");
                else if(str.startsWith("markref") == true)
                    fw.write("<" +str +"/>");
                else
                    fw.write("<" +str +">");
            }
            else
                fw.write(val);
        }
        fr.close();
        fw.close();
    }
}

write a code to create another file your expected filenma and copy all the contents of the output.xml file.

---------------------------
Vikrant Korde
3i Infotech, Vashi,
Mumbai, Maharashtra, India.

try

http://java.sun.com/j2se/1.4.2/docs/api/java/io/File.html#renameTo(java.io.File)