I’m having some difficulty in understanding nested loops so please explain as easy as possible. This is for finding 50 primes. Here’s the code.
public class FindPrimes
{
    public static void main(String[] args)
    {
        int nPrimes = 50; // The maxium number of primes requried

    OuterLoop:
        for (int i = 2; ; i++) // This loop runs forever
        {
            //Try dividing all integers from 2 to i-1
            for (int j = 2; j < i; j++)
            {
                if (i % j == 0) // This is true if j divides exactly
                    continue OuterLoop; // so exit the loop
            }
            // We only get here if we have a prime
            System.out.println(i); // So output the value
            if (--nPrimes == 0) // Decrement the count
            break;
        }
    }
}


Tell me I’m right or not. First OuterLoop runs and we have i = 2; in outerloop. Then inner loop executes where j = 2; now we come to if where we check (i%j == 0) in other words (2%2 == 0) so it is true it executes ****inue OuterLoop; now we have i = 3; here need some explanation down to inner loop perhaps j again initialized to 2. so in if statement this happens (i%j == 0) in other words (3%2 == 0) it is false we have a prime. I want to know this when i becomes i = 10; will it happen in inner loop (7%2 == 0) , (7%3 ==), (7%4 == ), (7%5 == 0), (7%6 == 0) . It will be checked that 7 is prime or not by dividing 7 with all numbers less then 7 in inner loop. Then again OuterLoop. If I’m wrong please explain this

Yes, since the variable j is being initialized in the for loop, it would start from 2 and scale up. The 7%2,7%3,7%4 would happen. However for the first time when i=2, it will not enter the inner loop as j!<i that is 2 is not <2. Hence 2 would be printed directly.

-eNJay