variable question

nulogix · June 25th, 2004, 02:31 PM

states.php---------------------------

<HTML>
<HEAD></HEAD>
<BODY>
<FORM ACTION="capitals.php" METHOD=POST>

<SELECT NAME=State>
<?php

$StatesOfTheUSA = array (1 => "Alabama", "Alaska", "Arizona"
for ($counter=1; $counter<51; $counter++) {
   echo"<OPTION>$StatesOfTheUSA[$counter]</OPTION>";
}
echo "</SELECT><BR><BR>";
for ($counter=1; $counter<51; $counter++) {
   echo"<INPUT TYPE=HIDDEN NAME='HiddenState[]'VALUE='$StatesOfTheUSA[$counter]'>";
}
echo "<INPUT TYPE=SUBMIT></FORM>";
?>
</BODY>
</HTML>

capitals.php--------------------------

<HTML>
<HEAD></HEAD>
<BODY>
<?php
$StateCapital = array (0 => "Montgomery", "Juneau", "Phoenix"
for ($counter=0; $counter<50; $counter++)
{
   if($HiddenState[$counter]==$State)
   {
      echo"The State capital is $StateCapital[$counter]";
   }
}
?>
</BODY>
</HTML>

in the states.php above inside the for loop i have a variable called $counter. There is also another for loop in the same page which also contains a variable called $counter. How does php know that these two variables are supposed to be different and not to replace the values within one with values from the other. Also when i click the submit page and go to capitals.php there is also a for loop with a variable called $counter. How does php know not to bring the $counter variable from the states.php page over to the capitals.php page and to not replace the values???

thanks

Snib · June 25th, 2004, 02:35 PM

PHP actually does replace the value of counter in states.php. It just doesn't matter, because you re-initialize it in the for statement.

PHP does not carry values to other pages without submitting a form or reading a session/cookie, AFAIK. Besides, it does not matter because you re-initialize it again in the for statement in capitals.php.

HTH,

Snib

<><