error in <form action='{$_SERVER['PHP_SELF']}

lanita · July 26th, 2004, 08:05 PM

Hello,
I'm confused how to send value of hidden field in form which post to itself.
I redirect from transact-article.php to upload.php with following info: redirect('upload.php?article=' . $artid);

in upload.php I have these code lines:
...
$article = $_GET['article'];
...
if (!isset($_POST['do_action'])){
echo " <form action='{$_SERVER['PHP_SELF']}' method='post' enctype='multipart/form-data'>\n",
<input type='file' name='userfile'>\n";
<input type='hidden' name='artic' value='{$article}' />\n",
</form>
...
//input file name and artcile id into db
$sql = "INSERT INTO uploads " .
"(research_data_id, filename)" .
"VALUES ('" . $_POST['artic']. "', '" . trim($file_path) . "')";

This code give an error of undefined index in line
$article = $_GET['article'];

I tried to change it to $_POST, didn't help. I need this line when I get article id from file
transact-article.php with redirect('upload.php?article=' . $artid);

Could you please help me to solve the problem with Undefined index: article?

And also, there is another big problem: when I upload second file to same article( I call upload.php again) the article id is not resent, how can I submit it to upload.php again? I though the hidden field should do the work, but, probably I don't call it properly..
Please, help

Thank you,

surendran · July 27th, 2004, 01:07 AM

Here i give you a small file uploading part (adding database also)
please first create a file

companyprofile.php

<script language="javascript">

</script>
<form name="form1" method="post" onsubmit="return pqr()">
<input type="text" readonly name="txtImgname" size="20" id="txtbox" value="">
<a title="Click here to upload image" href="javascript:uploadfile()">Upload</a>

</form>
-----------------------
//please create a file
-----upload.php------------

<head>
<meta http-equiv="Content-Type" content="text/html; charset=windows-1252">
<meta name="GENERATOR" content="Microsoft FrontPage 4.0">
<meta name="ProgId" content="FrontPage.Editor.Document">
<title>''... JOHNSON STEVENS AGENCIES LIMITED ...'''</title>
<link rel="stylesheet" type="text/css" href="images/jsal.css">
</head>
<script language="javascript">

</script>
<body topmargin="0" leftmargin="0" bgcolor="#C0C0C0">
<form enctype="multipart/form-data" name="form1" action="uploadresults.php" onsubmit="return onsubmitter()" method="post">
<input type="hidden" name="mid">
  <table border="0" class="companyprofile" width="100%">
   <tr>
    <td width="10%"> </td>
    <td width="80%">
      <p align="center"></td>
    <td width="10%"> </td>
  </tr>
     <tr>
    <td width="10%"> </td>
    <td width="80%">
      <p align="center"></td>
    <td width="10%"> </td>
  </tr>
  <tr>
    <td width="10%"> </td>
    <td width="80%">
      <p align="center"><input type="hidden" name="MAX_FILE_SIZE" value="3000000" />
Send this file: <input name="userfile" onkeypress="javascript:noenter()" id="txtbox" type="file" />
<input type="submit" onclick="avascript:return onsubmitter()" id="txtbox" value="Send File" /></td>
    <td width="10%"> </td>
  </tr>
     <tr>
    <td width="10%"> </td>
    <td width="80%">
      <p align="center"></td>
    <td width="10%"> </td>
  </tr>
</table>

</form>

-----create another file -----
uploadresults.php
-----------------
<head>
<meta http-equiv="Content-Type" content="text/html; charset=windows-1252">
<meta name="GENERATOR" content="Microsoft FrontPage 4.0">
<meta name="ProgId" content="FrontPage.Editor.Document">
<title>''... JOHNSON STEVENS AGENCIES LIMITED ...'''</title>
<link rel="stylesheet" type="text/css" href="images/jsal.css">
</head>
<body topmargin="0" leftmargin="0" bgcolor="#C0C0C0">
<?php
// In PHP versions earlier than 4.1.0, $HTTP_POST_FILES should be used instead
// of $_FILES.

$uploaddir = 'D:/jsal/php/sen/images/';
$uploadfile = $uploaddir . $_FILES['userfile']['name'];
print "<pre>";
if (move_uploaded_file($_FILES['userfile']['tmp_name'], $uploadfile)) {
    $msg="File Uploaded Successfully";
} else {
   $msg="File Uploaded Faild! <br>Please try again" ;
}
print "</pre>";

?>
<form name="form1">
<input type="hidden" name="imgval" value="<?echo $_FILES['userfile']['name'];?>">
<table border="0" class="companyprofile" width="100%">
   <tr>
    <td width="10%"> </td>
    <td width="80%">
      <p align="center"></td>
    <td width="10%"> </td>
  </tr>
  <tr>
    <td width="10%"> </td>
    <td width="80%">
      <p align="center"></td>
    <td width="10%"> </td>
  </tr>
     <tr>
    <td width="10%"> </td>
    <td width="80%">
      <p align="center"></td>
    <td width="10%"> </td>
  </tr>
     <tr>
    <td width="10%"> </td>
    <td width="80%">
      <p align="center"><b><?echo $msg;?></b></td>
    <td width="10%"> </td>
  </tr>
   <tr>
    <td width="10%"> </td>
    <td width="80%">
      <p align="center"></td>
    <td width="10%"> </td>
  </tr>
     <tr>
    <td width="10%"> </td>
    <td width="80%" align="center"> <input type="button" id="txtbox" onclick="window.close()" name="btnclose" value="Close">
      <p align="center"></td>
    <td width="10%"> </td>
  </tr>
   <tr>
    <td width="10%"> </td>
    <td width="80%">
      <p align="center"></td>
    <td width="10%"> </td>
  </tr>
</table>
<script LANGUAGE="javascript">
        window.opener.document.form1.txtimgname.value=docu ment.form1.imgval.value
</script>
</form>
</body>

after that you can add your details in your database...

lanita... if you need any information please send me a mail i'll help you.

surendran
(Anything is Possible)