PHP date arithmetic

takabyte · December 21st, 2005, 06:40 PM

I need to be able to determine an expiration date as being today plus a given subscription term. Given that:

$curdate=date("Ymd");
$term=365;

Why does the following not work? And what would?

$expdate= date($curdate, mktime(0, 0, 0, date("m"), date("d")+$term, date("y")));

anshul · December 23rd, 2005, 07:12 AM

What're you doing? Try this:

Quote:

quote:
<?php
$curdate = date("Ymd");
$term = 365;
$expdate = date( "Ymd", mktime(0, 0, 0, date("m"), date("d")+$term, date("y")) );
echo $curdate . "<br>" . $expdate;
?>

`~@#\^%&*/\.<.\/-|+|_!:;..=?>
Students' finances

takabyte · December 23rd, 2005, 03:08 PM

Thank you. Apparently my problem was in not understanding the "format" field in the "date" command. With your help, it works perfectly.

slouch · February 12th, 2009, 02:21 AM

You might also try this...

$expdate = date("Ymd",strtotime("+$term days"));

zeronexxx · February 12th, 2009, 02:54 PM

much better if you use strtotime function ...