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Old April 24th, 2009, 11:59 AM
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Default capturing file name after upload

Hello great programmer gurus!
I have this excellent code I want use so my clients can upload photos to their database.

The photos upload successfully. What I need to do is have the file name they uploaded to be entered into the mySQL database.

I have having trouble capturing the file name to be used in the insert query...

Here is my code..... I removed all passwords and names from query for security reasons...

I currently used $buff to try to capture that file name but doesnt work...

// Simple upload interface in PHP.
// Please send your comments to web.master@male.ru
// 07.11.2001

$UPLOAD_PATH = "/hiddden for security here/"; // directory on the server where are you going to upload files
// on Unix servers directories look like "/home/users/jack/files/"
// Don't forget about final slashes!!!

$UPLOAD_NUM = 1; // the number of upload fields

// display uploaded file list or errors during uploading
// and upload files
function displayUploadedList ()
global $UPLOAD_PATH,

$buff = '';
$error = 0;
for ($i = 0; $i < $UPLOAD_NUM; $i++)
$name = $HTTP_POST_FILES["File$i"]['name']; // this is the real name of your file
$tmp = $HTTP_POST_FILES["File$i"]['tmp_name']; // this is the temporary name of your file in temporary
// directory on the server

if (!is_uploaded_file ($tmp)) // is this temporary file really uploaded?

$buff .= "<li><span class=Text><b>".$name."</b></span>";

if (!@move_uploaded_file($tmp, $UPLOAD_PATH."/".$name)) // move temporary file to your upload directory
$error = 1;

if (strlen ($buff) == 0)
<P align=center class=bodycopy><font color="#FF0000"><b>ALERT! Select at least one file to upload.</b></font></P>
return false;
else if ($error)
<P align=center class=bodycopy><font color="#FF0000"><b>Some of selected files have not been uploaded.</b></font></P><br>
<P align=center class=bodycopy>Check existence of upload directory: <b><?=$UPLOAD_PATH?></b> and your permissions.</P>

return false;

<P align=center class=bodycopy><b>The following file has been uploaded:</b></font></P>
<P class=bodycopy align=center><b><?=$buff?></b></P>
<HR width=400>
<P align=center class=bodycopy>
<b><a href="javascript:window.close();">Close Window</a></P>

return true;

// display upload form
// this is not interesting function ;-(
function displayUploadForm () // display upload form,
global $UPLOAD_NUM;

$tablePre = "
<table border=0 cellspacing=0 cellpadding=0 align=center>
<td align=left valign=top>
<table border=1 cellspacing=1 cellpadding=6 align=center>
<tr bgcolor=#FFFFFF>


$displayed = '';
for ($i = 0; $i < $UPLOAD_NUM; $i++)
$displayed .= "<td class=TableElement bgcolor=#CCFFFF><input type=file name=File$i length=25></td></tr>";

$tableSuf = "
<p align=center><input type=submit name=Upload value=\"Upload Now!\" style=\"font-size: 10pt;\"></p>";

print $tablePre.$displayed.$tableSuf;

$name = $_GET["name"];

$con = mysql_connect("blocked out"," "," ");
if (!$con)
die('Could not connect: ' . mysql_error());
mysql_select_db(" ", $con);
mysql_query("UPDATE uploadtest SET test = $buff
WHERE item = 'WUC-2442R'");


<title>"ODD LIST" Photo Upload System</title>
<link rel="stylesheet" type="text/css" href="main.css">

<table border="0" cellspacing="1" cellpadding="5" align="center">
<td bgcolor="#FFFFFF" align=center>
print "<span class=subhead><b>Photo Upload</b></span><BR>
<span class=bodycopy>Upload the photo for the item you just entered.<BR><b>Photo MUST be 640 pixels wide x 480 pixels high</b></span>";
<form method=POST enctype="multipart/form-data" action="uploadfile.php" >
<td align="left" valign="top" bgcolor="#FFFFFF" height=100%>
displayUploadForm ();
<td align="left" valign="top" bgcolor="#FFFFFF" width="50%">

if (isset ($Upload)) // if user has clicked on Upload button we must try to upload something
displayUploadedList ();

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