This is my code

Private Sub cmdAdd_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles cmdAdd.Click
        myCommand = New OleDbCommand

        myCommand.Connection = myConnection
        Dim intPositin As Int16
        intPositin = myCurrencyManager.Position

        myCommand.CommandText = "insert into login (UserId, Password) values (@UserId, @Password)"
        myCommand.Parameters.Add("@UserId", txtUserName.Text)
        myCommand.Parameters.Add("@Password", txtPassword.Text)
        myConnection.Open()
        Try
            myCommand.ExecuteNonQuery()
        Catch ex As Exception
            MessageBox.Show(ex.ToString)
        End Try
        myConnection.Close()
        FillDataSetAndView()
        BindFields()
        myCurrencyManager.Position = myCurrencyManager.Count
        ShowPosition()
        StatusBar1.Text = "Record Added"
        Clear()
    End Sub

I am using Try...Catch to catch exception.
I get Following exception

Syntax error in INSERT INTO statement

What is wrong with code.
if you have another code for inserting above values give me that code

This question is posted at http://p2p.wrox.com/topic.asp?TOPIC_ID=49965

If you are going to post a question in more than one forum, you should post the actual question in one place, and references to it elsewhere. That way all action on the question will be in one place. This usually results in better, more robust discussions...