Hi fellas,
I am using the Jakarta commons fileupload jar to write an upload servlet.

I have created an html file where I upload a file as follows :
<form name="upload_form" enctype="multipart-form/data" method="post" action="servlet/UploadServlet2">
<center>

Please choose a file to upload <input type="file" name="upload_file">

<input type="submit" name="bttn_submit" value="Upload File">

</center>
</form>

On posting this form, I am calling the UploadServlet which has the following code :

import java.io.*;
import java.util.*;
import javax.servlet.*;
import javax.servlet.http.*;
import org.apache.commons.fileupload.*;

public class UploadServlet2 extends HttpServlet
    {
        protected void doGet(HttpServletRequest req, HttpServletResponse res) throws ServletException, IOException
        {
            doWork(req, res);
        }

        protected void doPost(HttpServletRequest req, HttpServletResponse res) throws ServletException, IOException
        {
            doWork(req, res);
        }

        private void doWork(HttpServletRequest req, HttpServletResponse res) throws ServletException, IOException
        {
            PrintWriter out = res.getWriter();
            out.println(req.toString());
            out.println("page loading");
            out.println(req.getContentType());
            out.println(req.getParameter("myText"));

            boolean isPart = FileUpload.isMultipartContent(req);
            out.println(isPart);
            if(isPart)
            {
                out.println("is multipart");
                DiskFileUpload upload = new DiskFileUpload();
                try
                {
                    List items = upload.parseRequest(req);
                    Iterator it = items.iterator();
                    while(it.hasNext())
                    {
                        FileItem item = (FileItem)it.next();
                        if(!(item.isFormField()))
                        {
                            out.println("success");
                        }
                    }
                }
                catch (FileUploadException e)
                {
                    // TODO Auto-generated catch block
                    System.out.println(e.getMessage());
                    out.println(e.getMessage());
                }
            }
            else
            {
                out.println("file not received");
            }

            out.flush();
            out.close();
        }
    }


But the output that I get is :

org.apache.coyote.tomcat4.CoyoteRequestFacade@7244 ca page loading application/x-www-form-urlencoded null false file not received

WHATS THAT SUPPOSED 2 MEAN ?
Where's the mistake in my code ?

How should I remedy the situation ?

Help needed immediately

Regards,
Sherbir

__________________
Regards,
Sherbir

This would be helpful

You can show a Browse and Upload Form buttonusing the following code.

<FORM ENCTYPE="multipart/form-data" method=post action="/utils/FileUploadServlet">
<INPUT TYPE="file" NAME="currentfilename">
<INPUT TYPE="submit" VALUE="upload">
</FORM>

It's easy to use a readily available class, which you can easily embed into your servlet for uploading the file. Download the most widely used File Upload package written by Jason Hunter at this URL http://www.servlets.com/resources/co...let/index.html